Probability Class 11
Master Probability Class 11 with comprehensive NCERT Solutions, Practice Questions, MCQs, Sample Papers, Case Based Questions, and Video lessons.
NCERT Solutions
Probability Class 11 – NCERT Solutions
Each question below opens its complete step-by-step Teachoo solution.
Ex 14.1
11 questionsEx 14.1 ,1
teachoo.
Ex 14.1, 1 CACHOO.cOM
A die is rolled. Let E be the event “die shows 4” and F be the event
“die shows even number”. Are E and F mutually exclusive?
Since die is rolled
So, S = {1, 2, 3, 4, 5, 6}
Given
E: die show 4
E= {4}
F : die show even number possible even number is 2,4 & 6
F = {2, 4, 6}
Ex 14.1, 2
teachoo.com
Ex 14.1, 2
A die is thrown. Describe the following events:
(i) A: a number less than 7
If the die is thrown,
possible outcomes are 1, 2, 3, 4,5,6
S = {1, 2, 3, 4, 5, 6}.
A:anumber less then 7
A={1, 2, 3, 4, 5, 6}
Ex 14.1, 3
Ex 14.1, 3 teachoo.com
An experiment involves rolling a pair of dice and recording the
numbers that come up. Describe the following events:
A: the sum is greater than 8, B: 2 occurs on either die
C: The sum is at least 7 and a multiple of 3.
Which pairs of these events are mutually exclusive?
Sample space when two dies are thrown
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),
g =} (32, (3,2), (3, 3), (3, 4), (3, 5), 3, 6),
~ )(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
A: The sum is greater than 8
Possible sum is greater than is 9, 10, 11, & 12
p= {2S)18515,4)(63)14.6)
~ ((5,5),(6,4),(5,6),(6,5),(6,6)
Ex 14.1, 4
Ex 14.1, 4 teachoo.com
Three coins are tossed once. Let A denote the event ‘three heads
show”, B denote the event “two heads and one tail show”. C denote
the event “three tails show” and D denote the event ‘a head shows
on the first coin”. Which events are
Finding A, B, C, D
When 3 coins are tossed, possible results are
S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
A: Three head shows
A = {HHH}
Ex 14.1, 5 (i)
Ex 14.1, 5 teachoo.com
Three coins are tossed. Describe
(i) Two events which are mutually exclusive.
Since 3 coins are tossed , possible outcomes are
S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
Two events which are mutually exclusive
Let A be the event getting only head
A = {HHH}
Let B be the event getting only tail
B= {TTT}
Ex 14.1, 5 (ii)
Three coins are tossed. Describe
(ii) Three events which are mutually exclusive and exhaustive.
Ex 14.1, 5 (iii)
Three coins are tossed. Describe
(iii) Two events, which are not mutually exclusive.
Ex 14.1, 5 (iv)
Three coins are tossed. Describe
(iv) Two events which are mutually exclusive but not exhaustive.
Ex 14.1, 5 (v)
Three coins are tossed. Describe
(v) Three events which are mutually exclusive but not exhaustive.
Ex 14.1, 6
Ex 14.1, 6 teachoo.com
Two dice are thrown. The events A, B and C are as follows:
A: getting an even number on the first die.
B: getting an odd number on the first die.
C: getting the sum of the numbers on the dice <5
Describe the events
If 2 dies are thrown then possible outcomes
are 1, 2, 3, 4, 5, 6 on both dies
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),
g =) 3 0, B, 2), (3, 3), (3, 4), (3, 5), (3, 6),
~ (4, 0), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Ex 14.1, 7
Ex 14.1, 7 teachoo.com
Refer to question 6 above,
State true or false: (give reason for your answer)
(i) A and B are mutually exclusive
From 16.2 ,6
(2, 1), (2, 2), (2, 3), (2, 4), (2,5), @, 6),
A=4 (4,1), (4,2), (, 3), (4,4), (4,5), 4, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6,5), (6 6)
(1, 1), (1, 2), 1, 3), G1, 4), (1, 5), (1,6),
B= 4 (3,1), (3,2), G, 3), G, 4), (3, 5), G, 6)
(5, 1), 6, 2), G, 3), G, 4), (5, 5), G, 6)
ANB=o
Ex 14.2
26 questionsEx 14.2, 1
Ex 14.2, 1 teachoo.com
Which of the following can not be valid assignment of probabilities
for outcomes of sample space S = { 01, Wz, W3, W4, Ws, We, W7,}
°) BPR
0.1 0.01 0.05 0.03 0.01 0.2 0.6
S= { Wy, Wo, 3, W4, Ws, We, Oz}
Sum of probability
= W1 + Wz + Wz +W4+ Ws + We + 7
= 0.1+0.01+0.05 + 0.03 +0.01+0.2+0.6
= 1.00
-. Assignment of probability is valid
Ex 14.2, 2
Ex 14.2, 2 teachoo.com
A coin is tossed twice, what is the probability that at least one tail
occurs?
When 2 coins are tossed,
Sample Space = S = {HH, HT, TH, HT}
n(S)=4
Let A be the event that at least 1 tail occurs
Hence A = {HT, TH, TT}
n(A) =3
P(A)= Number of outcomes favourable to A
( ) ~ Total number of possible outcomes
=n)
~ n(s)
3
“4
Ex 14.2, 3 (i)
Ex 14.2, 3 teachoo.com
A die is thrown, find the probability of following events:
(i) A prime number will appear,
When a die is thrown,
Sample space = S = {1, 2, 3, 4, 5, 6}
« n(S) = 6
Prime numbers between 1 to 6 are
2,3 and5
Let A be the event of that prime number appear
« n(A)=3
Ex 14.2, 3 (ii)
A number greater than or equal to 3 will appear,
View solutionEx 14.2, 3 (iii)
A number more than 6 will appear,
View solutionEx 14.2, 3 (iv)
A number more than 6 will appear,
View solutionEx 14.2, 3 (v)
A number less than 6 will appear.
View solutionEx 14.2, 4
Ex 14.2, 4 teachoo.com
A card is selected from a pack of 52 cards.
(a) How many points are there in the sample space?
Since these are 52 cards
these are 52 points in this sample space
n(S} = 52
Ex 14.2 ,5
Ex 14.2,5 teachoo.com
A fair coin with 1 marked on one face and 6 on the other and a fair
die are both tossed. Find the probability that the sum of numbers
that turn up is
(i) 3 Result | Result
of coin| of die
1 1 2
If the coin is tossed we get only 1 or 6 1 2 3
If a die is thrown we get 1, 2, 3, 4, 5, 6 1 3 4
1 4 5
1 5 6
Hence, 1 6 7
6 1 7
$= {i 4), (1, 2), (1, 3), (1, 4), (1, 5), (1, at 6 2 8
(6, 1), (6, 2), (6, 3), (6, 4), (6,5), (6, 6)) g 3 8
6 4 10
6 5 11
n(S)=12 6 6 PI
Ex 14.2, 6
teachoo.co
Ex 14.2, 6 "
There are four men and six women on the city council. If one council
member is selected for a committee at random, how likely is it that
it is a woman?
Total members = 10
Hence
n(S) = 10
Total women members =6
Let A be the event that women is selected
Hence n(A) =6
Ex 14.2, 7
Ex 14.2, 7 teachoo.com
A fair coin is tossed four times, and a person win Re 1 for each head
and lose Rs 1.50 for each tail that turns up. From the sample space
calculate how many different amounts of money you can have after
four tosses and the probability of having each of these amounts.
If a coin is tossed 4 times the following results are possible
Profit on Heads Loss on tails Amount of
money
4 head 0 tail 4x1=4 0x1.5=0 4-0=4
3 head 1 tail 3x1-+3 1x15=1.5 3-1.5=1.5
2 head 2 tail 2x1=2 2x1.5=3 2-3=-1
1 head 3 tail 1x1=1 3x15=45 1-45=-3.5
0 head 4 tail Ox1=0 4x15=6 0-6=-6
Hence, Different amount of money = {4, 1.5, —1, -3.5, —6}
Ex 14.2, 8
Ex 14.2, 8 teachoo.com
Three coins are tossed once. Find the probability of getting
(i) 3 heads
If 3 coins are tossed various combination possible are
S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
n(S) = 22= 8
Let A be the event of getting 3 head
A= {HHH}
on{A)=1
Probability of 3 heads = P(A)
Ex 14.2, 9
Ex 14.2, 9 teachoo.com
f= is the probability of an event, what is the probability of the
event ‘not A’
Let A be the event given
2
So, P(A) = —
Probability of not A
= P(A’)
=1-P(A)
-1-2
11
_ 11-2
"41
=2
“44
Ex 14.2, 10
Ex 14.2, 10 teachoo.com
A letter is chosen at random from the word ‘ASSASSINATION’. Find
the probability that letter is (i) a vowel
Letter in the word ASSASSINATION
Number of total letters in the given word = 13
n(S) = 13
Let A be the event getting vowels
So, A={A, A, A, |, |, O}
n(A)=6
Probability of getting vowels = P(A)
_ Number of vowels in word
~ Total number of letters in word
= nA)
~ n(S)
-&
“43
Ex 14.2, 11
Ex 14.2, 11 teachoo.com
In a lottery, person choses six different natural numbers at random
from 1 to 20, and if these six numbers match with the six numbers
already fixed by the lottery committee, he wins the prize. What is
the probability of winning the prize in the game? [Hint: order of the
numbers is not important.]
These are 20 natural number from 1 to 20
Total numbers = 20
Number to be chosen=6
Number of ways choosing 6 natural number from 1 to 20 = 7°C,
_ 20! 20! © 38760
~ 6120-6)! 6114! ways
Ex 14.2, 12 (i)
Ex 14.2, 12 teachoo.com
Check whether the following probabilities P(A) and P(B) are
consistently defined
(i) P(A)= 0.5, P(B) = 0.7, P(A n B) =0.6
P(A) & P(B) are consistently defined if
1. P(AMB)<P(A) & P(A 9 B) < P(B)
2. P(AUB)> P(A) & P(A U B) > P(B)
Given
P(A) = 0.5, P(B) = 0.7, P(A A B) = 0.6
Here,
P(A 1 B) > P(A).
Hence, P(A) and P(B) are not consistently defined.
Ex 14.2, 12 (ii)
Check whether the following probabilities P(A) and P(B) are consistently defined
P(A) = 0.5, P(B) = 0.7, P(A ∩ B) = 0.6
Ex 14.2, 13
Ex 14.2, 13 teachoo.com
Fill in the blanks in following table:
P(A) P(B) P(A B) P(AUB)
. 1 1 1
MG 3 rr
We know that
P(A U B) = P(A) + P(B) — P(A 0 B)
Putting values
1 1 1
P(AUB)=7 +2-—
543-1
7
Hence P(A UB) =——
lence P(. )=75
Ex 14.2, 14
Ex 14.2, 14 teachoo.com
Given P(A) == and P(B) = = Find P(A or B), if Aand B are mutually
exclusive events.
3 1
P(A)=— , P(B)=—
Since A and B are mutually excusive
So, P(AN B)=0
Now,
P(A or B) = P(A U B)
We know that
P(A U B) = P(A) + P(B) — P(A 2 B)
Ex 14.2, 15
Ex 14.2, 15 teachoo.com
If E & F are events such that P(E) = : , P(F)= ; and P(E and F) = er find:
(i) P(E or F)
P(E and F) = P(E 9 F) =—
We need to find
P(E or F) = P(E U F)
We know that
P(E U F) = P(E) + P(F)— P(E 9 F)
Putting values
11 1
P(EUF)=—+- --
4 2 8
Ex 14.2, 16
Ex 14.2, 16 teachoo.com
Events E and F are such that P(not E or not F) = 0.25, State whether
E and F are mutually exclusive.
Given that
P (not E or not F) = 0.25 Demorgan’s law
P(E’ UF’) = 0.25 If (A’N BY) =(A U By’
P (ENF) =0.25 or (A’ U B’) =(A 1 By’
1-P(EMF)=0.25 (By Demorgan law)
1-0.25 =P (ENF)
0.75 = P(E MF)
P (ENF) =0.75
Since P (ENF) #0
Ex 14.2, 17
teachoo.com
Ex 14.2, 17
A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B)
= 0.16. Determine
(i) P(not A),
P(A) = 0.42
P(not A)
=1- P(A)
=1-0.42
= 0.58
Ex 14.2, 18
Ex 14.2, 18 teachoo.com
In Class Xl of a school 40% of the students study Mathematics and
30% study Biology. 10% of the class study both Mathematics and
Biology. If a student is selected at random from the class, find the
probability that he will be studying Mathematics or Biology.
Let B be the event of student studying biology.
& M be the event of student studying maths
Hence
Probability student study maths = 40%
40
P(M)= 40% =— > =0.4
Probability student study biology = 30%
30
P(B) = 30% => =0.3
Ex 14.2, 19
Ex 14.2, 19 teachoo.com
In an entrance test that is graded on the basis of two examinations,
the probability of a randomly chosen student passing the first
examination is 0.8 and the probability of passing the second
examination is 0.7. The probability of passing at least one of them
is 0.95. What is the probability of passing both?
Let A be the event of passing the first examinations
& B be the event of passing second examination
Given
Probability of passing first exam = P(A) = 0.8
Probability of passing second exam = P(B) = 0.7
Given that
Probability of passing at least 1 of them = 0.95
Hence, P(A U B) = 0.95
Ex 14.2, 20
Ex 14.2, 20 teachoo.com
The probability that a student will pass the final examination in
both English and Hindi is 0.5 and the probability of passing neither
is 0.1. If the probability of passing the English examination is 0.75,
what is the probability of passing the Hindi examination?
Let E be the event of that a student passes in English
& H be the event that a student passes in Hindi
Given,
Probability of passing both English & Hindi = 0.5
P(EQ H)=0.5
Probability of passing in neither subject = 0.1
P(E’N H’) = 0.1
Ex 14.2, 21
Ex 14.2, 21 teachoo.com
In a class of 60 students, 30 opted for NCC, 32 opted for NSS and 24
opted for both NCC and NSS. If one of these studentsis selected at
random, find the probability that
(i) The student opted for NCC or NSS.
There are 60 studentin a class
n(S) = 60
Let A be the event that a student opted for NCC
& B be the event that a student opted for NSS
Given that
30 students opted for NCC
So, n(A) = 30
Examples
18 questionsExample, 1
Example 1 teachoo.com
Consider the experiment of rolling a die. Let A be the event ‘getting
a prime number’, B be the event ‘getting an odd number’. Write the
sets representing the events
(i) AorB
While rolling a die we can get 1, 2, 3, 4,5, 6
So, S = {1, 2, 3, 4, 5, 6},
Prime number between 1 to 6 are 2, 3 and5
So, A= {2, 3, 5}
Odd number between 1 to6 are 1,3 and5
So, B = {1, 3, 5}
Example 2
Example 2 teachoo.com
Two dice are thrown and the sum of the numbers which come up
on the dice is noted. Let us consider the following events associated
with this experiment
A: ‘the sum is even’.
B: ‘the sum is a multiple of 3’.
C: ‘the sum is less than 4’.
D: ‘the sum is greater than 11’.
Which pairs of these events are mutually exclusive?
If two dice are thrown then possible
outcomesare 1, 2, 3, 4, 5 & 6 on both dies
Hence
(1,1), (1, 2), (1,3), (1, 4), C1, 5), (1, 6)
(2, 1), (2, 2), (2,3), (2, 4), (2, 5), (2,6)
$= E 1), 3,2), B,3),G, 4), 3,5), GB, ;
(4, 1), (4, 2), (4,3), (4, 4), (4, 5), (4,6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6,4), (6,5), (6 6),
Example, 3
teachoo.com
Example 3
A coin is tossed three times, consider the following events.
A: ‘No head appears’, B: ‘Exactly one head appears’ and C: ‘At least
two heads appear’. Do they form a set of mutually exclusive and
exhaustive events?
If 3 coins are tossed , possible outcomes are
S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
A: no head appear
Hence only tail appear in all 3 times
So A={TTT}
Example 4
Example 4 teachoo.com
Let a sample space be S = {w,, Wy,..., We}.Which of the following
assignments of probabilities to each outcome are valid?
Outcomes W, W, Wz Wy Ws We
1 1 1 1 1 1
6 6 6 6 6
S= { 1, Wo, Wz, W4, Ws, We}
Sum of probability
=, + Wz + Wz + W4 t We + We
14114141
a
6 6 66 66
=°
“6
=1
«. Assignment of probability is valid
Example 5
Example 5 teachoo.com
One card is drawn from a well shuffled deck of 52 cards. If each
outcome is equally likely, calculate the probability that card will be
(i) a diamond
5432
weee: A
ss 2 a a4 + ¢ +
Since there 52 cards > a
"
a
n(S) = Total number 9
of cards = 52
s
v
There are 13 diamond cards
Let A be event that diamond card is withdrawn
So, n(A) = 13
Example, 6
Example 6 teackoo.com
A bag contains 9 discs of which 4 are red, 3 are blue and 2 are yellow.
The discs are similar in shape and size. A disc is drawn at random
from the bag. Calculate the probability that it will be
(i) red,
There are 9 discs of which
4are red
3 are blue
& 2 are yellow
Total number of possible outcomes is 9
n(sj=9
Let A be the event that the disc is red
B be the event that the disc is yellow
C be the event that the disc is blue
Example 7
Example 7 teachoo.com
Two students Anil and Ashima appeared in an examination. The
probability that Anil will qualify the examination is 0.05 and that
Ashima will qualify the examination is 0.10. The probability that
both will qualify the examination is 0.02. Find the probability that
(a)Both Anil and Ashima will not qualify the examination.
Let E be the event that Anil will qualify the examination
& F be the event that Ashima will qualify the examination
Given
Probability that Anil will qualify the exam = P(E) = 0.05
Probability that Ashima will qualify the exam = P(F) = 0.10
Example 8
Example 8 teachoo.com
A committee of two persons is selected from two men and two
women. What is the probability that the committee will have
(a) no man?
If no man is selected, it means only women are selected
So, we have to select 2 women
Total number of persons =2+2=4
Number of persons to be selected = 2
P(no man is selected) - Number of ways both women is selected (1)
Total number of ways
Total Number of ways = *C,
— ab 4h 4x BX 2g
24-2)! 22) 2x 1x 2
Example 9
Example 9 teackoo.com
On her vacations Veena visits four cities (A, B, C and D) in arandom
order. What is the probability that she visits
(i) A before B?
4 cities can be visited in any of following order
ABCD, ABDC, ACBD, ACDB, ADBC, ADCB,
S= BACD, BADC, BDAC, BDCA, BCAD, BCDA,
~ ) CABD, CADB, CBDA, CBAD, CDAB, CDBA,
DABC, DACB, DBCA, DBAC, DCAB, DCBA
n(S) = 24
Let E be the event that “she visits A before B“
ABCD, ABDC, ADBC, ACDB, ADBC, ADCB,
Hence, E= | CABD, CADB, CDAB,
DABC, DACB, DCAB,
Example 10
Example 10 teachoo.com
Find the probability that when a hand of 7 cards is drawn from a well
shuffled deck of 52 cards, it contains
{i) all Kings
7 cards are to be chosen from 52 cards
Total number of combinations (hands) possible = 52C,
_ 82th
7\(52-7)! 7145!
Let A be the event that all kings are selected
There are only 4 kings in a pack of 52 cards
Example 11
Example 11 teachoo.com
If A, B, C are three events associated with a random experiment,
prove that P(A U B U C) = P(A) + P(B) + P(C) - P(An B) - P(An C)
-P(BNC)+P(ANBNC)
Let BUC=E
So, P(AUBUC)=P(AU E)
= P(A) + P(E)— P(A o E)
= P(A) + P(E)- P(A (BU C))
=P(A)+P(E)—P(ANB)U(ANC)) (1)
We find P(E) & P((A 9 B) U (A C)) separately
Finding P(E)
P(E)=P(BUC)
= P(B) + P(C) - P(Bn C) (2)
Example 12
Example 12 teachoo.com
In a relay race there are five teams A, B, C, D and E.
(a) What is the probability that A, B and C finish first, second and
third, respectively.
3 teams will win from 5 teams
Hence
Total number of orders = °P.,
5!
~ (5-3)!
5!
“21
_5X4X3 x2!
~ 2!
=60
Question 1
teachoo.com
Example 1
Two coins (a one rupee coin and a two rupee coin) are tossed
once. Find a sample space.
Both coins are same,
either head comes or tail comes
Possible combination
when 2 coins are tossed
We denote head by H
a tall byT | coin 1 | coin 2 |
H H
H T
T H
Hence the sample space is T T
S = {(H,H), (H,T), (TH), (T.T)}
Question 2
Example 2 teackoo.com
Find the sample space associated with the experiment of rolling a
pair of dice (one is blue and the other red) once.
Also, find the number of elements of this sample space.
Possible results on both dies are
1, 2, 3, 4, 5, 6 only
Hence sample size is
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),
5 -] BD, (3, 2), 8, 3), 3, 4), (3,5), B, 6),
~ ) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Number of elements in sample space = 6 x 6
=36
Question 3 (i)
Example 3 teackoo.com
In each of the following experiments specify appropriate sample space
(i) A boy has a 1 rupee coin, a 2 rupee coin and a 5 rupee coin in his
pocket. He takes out two coins out of his pocket, one after the
other.
Let Q denote a 1 rupee coin,
H denotes a 2 rupee coin Q H
& R denotes a 5 rupee coin. Q R
H Q
He takes out two coins, one after the other H R
R Q
All possible outcomes are R H
S = {QH, QR, HQ, HR, RQ, RH}
Question 3 (ii)
Example 3
In each of following experiments specify appropriate sample space
(ii) A person is noting down the number of accidents along a busy highway during a year
Question 4
Example 4 teackoo.com
A coin is tossed. If it shows head, we draw a ball from a bag
consisting of 3 blue and 4 white balls; if it shows tail we throw a
die. Describe the sample space of this experiment.
The results on tossing coin
are heads and tails
Let heads be denoted by H
& tails by T
Also, 3 blue & 4 white balls
be denoted by B,, B,, B, and W,, W,, W; and W,
Results of die are 1, 2,3, 4,5, 6
Question 5
Example 5 teachoo.com
Consider the experiment in which a coin is tossed repeatedly until
a head comes up. Describe the sample space.
Let Head be H
Coin tossed
& Tail be T
‘time | tine | time | time time | - i
coin tossed
H - - - -
T H - - - Head Tail
T T H 7 - coin tossed
T T T H - ——
Head Tail
T T T T H
S = {H, TH, TTH, TTTH, TTTTH....}
Miscellaneous
13 questionsMisc 1
Misc 1 teachoo.com
A box contains 10 red marbles, 20 blue marbles and 30 green marbles.
5 marbles are drawn from the box, what is the probability that
(i) all will be blue?
5 marbles are to be chosen from 60 (10 red + 20 blue + 30 green)
Hence
n(S) = °C,
Let A be the event that all are blue
Hence out of 20 blue marbles 5 will be chosen
n(A) = 27°C,
20
= m4) __€s
P(A)= ns) ¢,
Misc 2
Misc 2 teachoo.com
4 cards are drawn from a well-shuffled deck of 52 cards. What is the
probability of obtaining 3 diamonds and one spade?
Total 4 cards are to be selected out of 52 cards
Hence
Total ways to select 4 cards= °C,
We need to select 3 diamond card & 1 spade card
Total number of diamond card = 13
Number of diamond card to be selected = 3
Total ways to select 3 diamond card = °C,
Misc 3
Misc 3 teachoo.com
A die has two faces each with number ‘1’, three faces each with
number ‘2’ and one face with number ‘3’. If die is rolled once,
determine
(i) P(2)
A normal die has 6 faces 1, 2, 3, 4, 5, 6
But in this question
die has following 6 faces
1, 1,2, 2, 2,3
n(S)=6
We need to find P(2)
There are 3 three 2’s
Misc 4
Misc 4 teachoo.com
In a certain lottery 10,000 tickets are sold and ten equal prizes are
awarded. What is the probability of not getting a prize if you buy
(a) one ticket
Since, 1 ticket is chosen out of 10000 tickets
n(S) = 10000¢ |
10000! 10000 x 9999!
=———_ = ———— = 10000
119999! 1x 9999!
Now out of 10000 tickets only 10 have a prize
Hence number of tickets not having prize
= 10000 — 10
= 9990
Misc 5
Misc 5 (a) Method 1 teachoo.com
Out of 100 students, two sections of 40 and 60 are formed. If you and
your friend are among the 100 students, what is the probability that
(a) you both enter the same sections?
Both enter same section
Both enter Section A Both enter Section B
Pott [Friends [other [La Total Fonds |Other
All All
100 2 98 100 2 98
students students
Studentin Studentin
40 2 38 . 60 2 58
Section A Section B
n{S) = *°°Cag n(S) = Ceo
Let A be event that both Let B be event that both
enter sectionA enter section B
n{A) = C35 n(B) = Cog
Misc 6
Misc 6 teachoo.com
Three letters are dictated to three persons and an envelope is
addressed to each of them, the letters are inserted into the envelopes
at random so that each envelope contains exactly one letter. Find the
probability that at least one letter is in its proper envelope.
Let the envelope be denoted by A, B, C
and the corresponding letters are a, b, c
The letters are inserted into the envelopes at random,
& each envelope contain exactly one letter
Possible combinations can be
Aa Bb Cc
Aa Be Cb
Ab Ba Cc
Ab Bc Ca
Ac Bb Ca
Ac Ba Cb
So, Total number of possible cases = 6
Misc 7 (i)
Misc7 teachoo.com
A and B are two events such that P(A) = 0.54, P(B) = 0.69 and
P(A B) = 0.35. Find
(i) P(A U B)
Given
P(A) = 0.54, P(B) = 0.69, P(A N B) = 0.35
We know that
P (AU B) = P(A) + P(B) - P(A 0 B)
Putting values
= 0.54 + 0.69 - 0.35
= 0.88
Misc 7 (ii)
Misc 7
A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A ∩ B) = 0.35. Find
(ii) P(A′ ∩ B′)
Misc 7 (iii)
Misc 7
A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A ∩ B) = 0.35. Find
(iii) P(A ∩ B′)
Misc 7 (iv)
Misc 7
A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A ∩ B) = 0.35. Find
(iv) P(B ∩ A′)
Misc 8
Misc 8 teachoo.com
From the employees of a company, 5 persons are selected to
represent them in the managing committee of the company.
Particulars of five persons are as follows:
S.No Name Sex Age in years
1. Harish M 30
2. Rohan M 33
3. Sheetal F 46
4. Alis F 28
5. Salim M 41
A person is selected at random from this group to act as a
spokesperson. What is the probability that the spokesperson will
be either male or over 35 years?
Total number of persons = 5
So, n(S)=5
Misc 9
teachoo.com
Misc 9
If 4-digit numbers greater than 5,000 are randomly formed from
the digits 0, 1, 3, 5, and 7, what is the probability of forming a
number divisible by 5 when,
(i) the digits are repeated?
Digit number greater than 5000 can
be formed with either 5 in beginning
or 7 in beginning
5
or
7
Misc 10
teachoo.com
Misc 10
The number lock of a suitcase has 4 wheels, each labelled with ten
digits i.e., from 0 to 9. The lock opens with a sequence of four digits
with no repeats. What is the probability of a person getting the
right sequence to open the suitcase?
There are 10 digits out of which 4 digits to be chosen with no
repeats
Hence,
n(S) = Total 4 digit numbers out 10 digits
=10p, {We used permutation as order is important)
10! 10!_ 10x 9x 8x 7x 6!
“(o-4)! 6! 6! = 5040
Sample Space
17 questionsQuestion 1
Ex 16.1, 1 teachoo.com
Describe the sample space for the indicated experiment:
A coin is tossed three times.
When a coin is tossed,
we get either heads or tails
H H H
Let heads be denoted by H H H T
and tails cab be denoted by T H T H
T H H
Hence the sample space is
T T H
S = {HHH,
H T T
HHT, HTH, THH,
T H T
TTH, HTT, THT,
T T T
TIT}
Question 2
Ex 16.1, 2 teachoo.com
Describe the sample space for the indicated experiment: A die is
thrown two times.
When a die is thrown,
either of 1, 2, 3, 4, 5, 6 is possible
The results of 2 Dies can be as follows
(1, 1), (1, 2), (1, 3), (2, 4), (1, 5), (1, 6),
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),
5 = |B 1 (3,2), 8,3), (3, 4), (3,5), (3, 6),
~ ) (4,1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Question 3
Ex 16.1, 3 teachoo.com
Describe the sample space for the indicated experiment: A coin is
H H H H
When a coin is tossed, H H H T
H H T H
we get either heads or tails H H T T
H T H H
Let head d d by H H 7 4 T
et head denoted by H T T H
& tail denoted by T H T T T
T H H H
T H H T
T H T H
Hence, T H T T
T T H H
T T H T
HHHH, HHHT, HHTH, HHTT, T T T H
Ss HTHH, HTHT,HTTH,HTTT, T T T T
~ ) THHH, THHT, THTH, THTT, J
TTHH, TTHT, TTTH, TTTT
Question 4
teachoo.com
Ex 16.1, 4
Describe the sample space for the indicated experiment: A coin is
tossed and a die is thrown.
When a coin is tossed either we can get heads or tails
Let heads be denoted by H
and tails by T
When coin| When die
tossed rolled
Similarly when a die is rolled H 1
the possible results are T 2
1, 2, 3,4, 5,6 3
4
5
6
Question 5
teachoo.com
Ex 16.1, 5
Describe the sample space for the indicated experiment: A coin is
tossed and then a die is rolled only in case a head is shown on the coi
When a coin is tossed
When a coin is tossed ,
either we get head or tail H T
|
Lets head be denoted by H Die thrown
& tail be denoted by T |
H1
H2
According to a question H3
When head is shown then a die is rolled ie
H6
Hence,
Total number of sample space S$ associated with the experiment
S = {H1, H2, H3, H4, H5, H6, T}
Question 6
Ex 16.1, 6 teachoo.com
2 boys and 2 girls are in Room X, and 1 boy and 3 girls in Room Y.
Specify the sample space for the experiment in which a room is
selected and then a person.
Room X Room Y
Let B,, B, and G,, G, are the B,, and G;, G,, G, are the
boys & girls in room X boys & girls in room Y
Possible outcomes Possible outcomes
When room X is selected then When room Y is selected then a
a person person
{XB,, XB,, XG,, XG,} {YB3, YG3, YG,, YG5}
Hence
The sample space S is
S = {XB,, XB,, XG,, XG,, YB, YG, YG,, YG,}
Question 7
Ex 16.1, 7 teachoo.com
One die of red colour, one of white colour and one of blue colour are
placed in a bag. One die is selected at random and rolled, its colour an
the number on its uppermost face is noted. Describe the sample space
Let R denote red die
W denote white die
& B denote blue die
When a die is rolled,
possible outcomes are 1, 2, 3, 4,5, 6
Possible outcome when red die is selected
{R1, R2, R3, R4, R5, R6}
Possible outcomes when white die is selected
{W1, W2, W3, W4, WS, W6}
Question 8 (i)
Ex 16.1, 8 teachoo.com
An experiment consists of recording boy-girl composition of families
with 2 children.
(i) What is the sample space if we are interested in knowing
whether it is a boy or girl in the order of their births?
A family with 2 child may be | ar child 2m child |
either girl or boy
B B
B G
Let G denote girl child
G B
& B denote boy child
G G
S = {BB, BG, GB, GG}
Question 8 (ii)
What is the sample space if we are interested in the number of girls in the family?
View solutionQuestion 9
teachoo.com
Ex 16.1, 9
A box contains 1 red and 3 identical white balls. Two balls are
drawn at random in succession without replacement. Write the
sample space for this experiment.
A box contain 1 red & 3 identical white balls
Let R denote the red ball
& W denote the identical white ball
The two balls selected at random in succession without
replacement | 2% ball | 2% ball
R Ww
Th | i
e sample space ais w R
S = {RW, WR, WW} Ww Ww
Question 10
Ex 16.1, 10 teachoocom
An experiment consists of tossing a coin and then throwing it second
time if a head occurs. If a tail occurs on the first toss, then a die is
rolled once. Find the sample space.
If a coin tossed there can be either head or tail
Let head denote by H
& tail denote by T
Similarly
If a die is rolled possible outcomes
are 1, 2,3,4,5,&6
Question 11
Ex 16.1, 11 teachoo.com
Suppose 3 bulbs are selected at random from a lot. Each bulb is
tested and classified as defective (D) or non-defective (N). Write
the sample space of this experiment?
2 bub] 3b
3 bulbs are to be selected at random D D D
Each bulb is tested D D N
D - denote for defective D N D
& N - denote for non-defective D N N
N D D
N D N
N N D
N N N
Sis the sample space of this experiment
S = {DDD, DDN, DND, DNN, NDD, NDN, NND, NNN}
Question 12
teachoo.com
Ex 16.1, 12
A coin is tossed. If the outcome is a head, a die is thrown. If the die
shows up an even number, the die is thrown again. What is the
sample space for the experiment?
When a coin is tossed, either head comes as tail
Let denote head by H
& Tail by T
Similarly when a die is rolled,
the possible results are
1,2,3,4,5&6
Question 13
Ex 16.1, 13 teachoo.com
The numbers 1, 2, 3 and 4 are written separately on four slips of
paper. The slips are put in a box and mixed thoroughly. A person
draws two slips from the box, one after the other, without
replacement. Describe the sample space for the experiment.
Four slips marked as 1, 2, 3, 4, are in the box
The slips are put in the box & mixed
A person draws two slips one after other without replacement
that means (1, 1}, (2, 2}, (3, 3) & (4, 4} are not possible
S be the sample space with the experiment
(1, 2), (1, 3), (1, 4),
ga) (2 Ms(2, 3), (2,4),
~ ) (3,4), (3, 2), (3, 4),
(4, 1), (4, 2), (4, 3)
Question 14
Ex 16.1, 14 teachoo.com
An experiment consists of rolling a die and then tossing a coin once
if the number on the die is even. If the number on the die is odd, the}
coin is tossed twice. Write the sample space for this experiment.
If a die is rolled
Possible outcomes are
1,2,3,4,5&6
Similarly if a coin is tossed
There can be either Head or tail
Let H denotes head
& T denotes tail
Question 15
teachoo.com
Ex 16.1, 15
A coin is tossed. If it shows a tail, we draw a ball from a box which
contains 2 red and 3 black balls. If it shows head, we throw a die.
Find the sample space for this experiment.
tf a coin is tossed there can be either head or tail
Let head be denoted by H
& tail be denoted by T
R, & R, be denoted by red ball
& B,, B,, and B, be denoted by black ball
If a die is thrown, the possible outcomes are
1,2,3,4,5,6
Question 16
Ex 16.1, 16 teachoo.com
A die is thrown repeatedly until a six comes up. What is the sample
space for this experiment?
If a die is throw possible outcomes are
Die rolled
1, 2,3,4,5,6
6 Not 6
6 Die rolled
Not 6 6 - 6 Not 6
Not 6 Not 6 6 |
Die rolled
6 Not 6
Why Learn This With Teachoo?
Probability studies uncertainty by describing random experiments, sample spaces and events. Students learn to construct outcomes, perform algebra of events and calculate probabilities using equally likely cases, set formulas, permutations and combinations. Teachoo provides solutions for Exercises 14.1 and 14.2, NCERT examples, miscellaneous questions and concept-wise practice on sample spaces, event types and probability calculations.
Random experiments and sample spaces
A random experiment has a known set of possible outcomes but an individual result cannot be predicted with certainty in advance. The sample space S is the set of all possible outcomes. An event A is a subset of S. A simple event contains one outcome; a compound event contains more than one.
The impossible event is ∅ and has probability 0. The sure event is S and has probability 1. The complement A′ contains outcomes in S that are not in A. Writing the sample space clearly is the most important first step, because every later count depends on it.
Outcomes can be listed using braces, tables, grids or tree diagrams. The representation should preserve order when order matters. For two dice, (2, 5) and (5, 2) are different ordered outcomes even though their sum is the same.
Algebra of events
The union A ∪ B means A or B or both. The intersection A ∩ B means both A and B. Events are mutually exclusive if A ∩ B = ∅. A collection of events is exhaustive if their union is S. Mutually exclusive and exhaustive describe different properties; events can satisfy one without satisfying the other.
De Morgan’s laws connect complements:
-
(A ∪ B)′ = A′ ∩ B′;
-
(A ∩ B)′ = A′ ∪ B′.
These results help translate phrases such as “neither,” “not both” and “at least one.”
Classical probability
When a finite sample space has equally likely outcomes,
P(A) = n(A)/n(S).
Every probability lies between 0 and 1. Complementary probability gives P(A′) = 1 − P(A). The addition rule is
P(A ∪ B) = P(A) + P(B) − P(A ∩ B).
If A and B are mutually exclusive, the intersection term is zero. Students should not use counting ratios unless the elementary outcomes are equally likely.
Counting outcomes efficiently
Simple coin, die and card experiments can often be listed. Larger sample spaces require the fundamental counting principle, permutations or combinations. Use combinations when a hand or group is selected without order; use permutations when order changes the outcome. Count favourable cases under exactly the same assumptions as total cases.
Many “at least one” questions are easiest through the complement: 1 minus the probability of none. However, students should define the complement before calculating to avoid subtracting the wrong event.
Topics covered on Teachoo
-
Exercises 14.1 and 14.2, examples and miscellaneous questions;
-
formation and interpretation of sample spaces;
-
events as subsets of a sample space;
-
algebra of events;
-
simple, compound, sure and impossible events;
-
mutually exclusive and exhaustive events;
-
basic classical probability formula;
-
complements and set-based formulas;
-
probability using permutations;
-
probability using combinations.
Learning outcomes
Students should be able to define a random experiment, construct a complete sample space and represent events using set notation. They should perform union, intersection and complement operations, identify event relationships and calculate classical probabilities. They should use counting methods appropriately and interpret a probability in words.
Why is this chapter important?
Probability supports statistics, data science, risk analysis, genetics, finance and decision-making. It also appears throughout Class 12 and competitive examinations. The Class 11 chapter builds the event language needed for conditional probability, independence and probability distributions later.
How Teachoo helps you prepare
Teachoo separates sample-space construction, event algebra and calculation methods. Begin each solution with S and the event definition, even when the result appears obvious. For equally likely outcomes, count n(S) and n(A) independently and simplify the ratio at the end.
Use serial-order NCERT solutions for textbook exercises and concept-wise practice for set formulas, permutations and combinations. After reading a solution, rebuild the sample space using a table or tree to make sure no outcome is missing or repeated.
School-exam, JEE and competency preparation
School exams test sample spaces, event operations and basic probability. JEE questions combine counting, set relations and multi-stage experiments. The main challenge is often defining outcomes correctly, not the final fraction.
Competency questions may involve games, surveys, quality checks or selections. Ask whether outcomes are equally likely. If not, classical favourable-over-total counting may be invalid. Translate “at least,” “at most,” “exactly,” “either,” “neither” and “both” into events before counting.
For card questions, know the structure of a standard deck but state relevant counts. For dice or coins, distinguish objects if the experiment does. In multi-stage experiments, a tree diagram can reveal conditional branches even before formal conditional probability is introduced.
Quick revision checklist
Write sample spaces for coins, dice and selections; define unions, intersections and complements; classify event pairs; verify De Morgan’s laws on an example; calculate probabilities by listing, combinations and permutations; and solve two “at least one” questions using complements.
Common mistakes to avoid
Do not omit outcomes from S or count the same outcome twice. Do not confuse mutually exclusive with independent; independence is a different concept. For “A or B,” subtract the overlap unless the events are disjoint. Use combinations for unordered selections. Never report a probability below 0 or above 1 without recognising an error.
Deeper reasoning and concept connections
Study Probability through comparison and justification. Place two related examples side by side, identify the decisive difference and explain why one method works in each case. Then create a new example and a deliberate non-example. This forces the definition to do real work and exposes gaps that passive reading hides.
Students should also practise reversing questions. After solving for an answer, ask what question could have produced it, whether more than one answer is possible and which extra condition would make the result unique. Reverse reasoning develops flexibility and is especially useful for missing-value, assertion–reason and error-analysis questions. The goal is to understand the network of ideas, not merely the order of a textbook solution.
How to solve unfamiliar and competency-based questions
Begin by separating facts from conclusions. Facts are given by the question or a known property; conclusions must be derived. Draw or rewrite the problem so each fact has a visible place. If several methods are possible, prefer the one with fewer assumptions and an easy final check. Record intermediate results rather than doing everything mentally.
Competency questions often change context without changing mathematics. Replace names and story details with variables, shapes, sets or data values. After solving, restore the context and check feasibility: counts should be whole where required, lengths and areas should have suitable units, probabilities should lie between 0 and 1, and constructed figures should satisfy every stated condition.
What complete mastery looks like
For Probability, a student should be able to define the central ideas in simple language, recognise them in different representations, solve routine questions accurately and explain the method used. They should also be able to correct a flawed solution, create an example satisfying given conditions and combine two ideas from the chapter in one problem. A reliable mastery test is to solve one direct question, one application question and one reasoning question without looking at notes, then explain all three aloud or in writing.
Keep a compact error log with four labels: concept, interpretation, calculation and presentation. Reattempt each error after a gap instead of rereading the answer immediately. Improvement comes from correcting the decision that caused the mistake, not from repeating questions whose method is already known.
Additional frequently asked questions
What should a student know before starting Probability?
Revise the definitions, number operations, diagrams or notation used at the beginning of the chapter. The prerequisite list should be short: if an earlier skill blocks progress, repair that skill with two or three focused questions and return to the chapter.
How can a student check an answer in Probability?
Use an independent check whenever possible: substitute the result, reverse the operation, estimate its size, compare it with the figure, test a simpler case or solve using another representation. A check should examine the mathematical condition, not merely repeat the same arithmetic.
How many questions are enough for strong preparation?
There is no fixed number. Stop counting questions and track coverage: every concept, every standard method, at least one mixed problem, one competency-based problem and every previously incorrect type should be solved independently. Ten varied, analysed questions are more valuable than fifty copied solutions.
How should Teachoo solutions be used without becoming dependent on them?
Attempt the question first and mark the exact step where progress stops. Read only enough of the solution to repair that step, close it and restart the question. Finally, solve a similar problem without help. This turns a solution into feedback rather than a substitute for thinking.
Frequently asked questions
What is a sample space?
It is the set of all possible outcomes of a random experiment.
What is the difference between an outcome and an event?
An outcome is one possible result; an event is a set of one or more outcomes.
Are mutually exclusive events the same as exhaustive events?
No. Mutually exclusive events cannot occur together; exhaustive events collectively cover the entire sample space.
When is P(A) = n(A)/n(S) valid?
It is valid for a finite sample space whose elementary outcomes are equally likely.
Does Teachoo use permutations and combinations in probability?
Yes. Teachoo has dedicated concept-wise sections for probability questions requiring permutations or combinations.
What is the fastest method for “at least one” probability?
Often it is P(at least one) = 1 − P(none), provided the complement is counted correctly.
Probability becomes reliable when the experiment, sample space and event are defined before any formula is applied.