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Ex 16.3, 14 - Chapter 16 Class 11 Probability (Term 2)

Last updated at March 16, 2023 by

Ex 16.3, 14 - Given P(A) = 3/5, P(B) = 1/5. Find P(A or B)

Ex 16.3, 14 - Chapter 16 Class 11 Probability - Part 2

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Ex 16.3, 14 Given P(A) = 3/5 and P(B) = 1/5. Find P(A or B), if A and B are mutually exclusive events. P(A) = 3/5 , P(B) = 1/5 Since A and B are mutually excusive So, P(A ∩ B) = 0 Now, P(A or B) = P(A ∪ B) We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B) Putting values P(A ∪ B) = 3/5 + 1/5 – 0 = (3 + 1)/5 = 4/5 Hence, P(A ∪ B) = 𝟒/𝟓

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