1. Chapter 16 Class 11 Probability
  2. Serial order wise
  3. Ex 16.3

Ex 16.3, 14 - Chapter 16 Class 11 Probability

Last updated at Feb. 11, 2020 by

Slide48.JPG

Slide49.JPG

Subscribe to our Youtube Channel - https://you.tube/teachoo

  1. Chapter 16 Class 11 Probability
  2. Serial order wise

    3. Ex 16.3

    Examples →

Transcript

Ex 16.3, 14 Given P(A) = 3/5 and P(B) = 1/5. Find P(A or B), if A and B are mutually exclusive events. P(A) = 3/5 , P(B) = 1/5 Since A and B are mutually excusive So, P(A ∩ B) = 0 Now, P(A or B) = P(A ∪ B) We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B) Putting values P(A ∪ B) = 3/5 + 1/5 – 0 = (3 + 1)/5 = 4/5 Hence, P(A ∪ B) = 𝟒/𝟓

Chapter 16 Class 11 Probability
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.