1. Chapter 16 Class 11 Probability
  2. Serial order wise
  3. Ex 16.3

Ex 16.3, 14 - Chapter 16 Class 11 Probability

Last updated at May 29, 2018 by

Ex 16.3, 14 - Given P(A) = 3/5, P(B) = 1/5. Find P(A or B) - Using formulae of sets

Slide47.JPG

  1. Chapter 16 Class 11 Probability
  2. Serial order wise

    3. Ex 16.3

    Examples →

Transcript

Ex 16.3, 14 Given P(A) = 3﷮5﷯ and P(B) = 1﷮5﷯. Find P(A or B), if A and B are mutually exclusive events. P(A) = 3﷮5﷯ , P(B) = 1﷮5﷯ Since A and B are mutually excusive So, P(A ∩ B)= 0 Now, P(A or B) = P(A ∪ B) We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B) putting values P(A ∪ B) = 3﷮5﷯ + 1﷮5﷯ – 0 = 3 + 1﷮5﷯ = 4﷮5﷯ Hence, P(A ∪ B) = 𝟒﷮𝟓﷯

Chapter 16 Class 11 Probability
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.