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Ex 14.2, 14 - Chapter 14 Class 11 Probability
Last updated at May 29, 2023 by Teachoo
Ex 14.2
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Ex 14.2, 3 (i) Important
Ex 14.2, 3 (ii)
Ex 14.2, 3 (iii)
Ex 14.2, 3 (iv)
Ex 14.2, 3 (v)
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Ex 14.2, 11 Important
Ex 14.2, 12 (i)
Ex 14.2, 12 (ii) Important
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Ex 14.2, 14 Important You are here
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Ex 14.2, 20 Important
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Chapter 14 Class 11 Probability
Serial order wise
- Ex 14.1
-
Ex 14.2
- Examples
- Miscellaneous
- Sample Space
Transcript
Ex 14.2, 14 Given P(A) = 3/5 and P(B) = 1/5. Find P(A or B), if A and B are mutually exclusive events. P(A) = 3/5 , P(B) = 1/5 Since A and B are mutually excusive So, P(A ∩ B) = 0 Now, P(A or B) = P(A ∪ B) We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B) Putting values P(A ∪ B) = 3/5 + 1/5 – 0 = (3 + 1)/5 = 4/5 Hence, P(A ∪ B) = 𝟒/𝟓
