Ex 16.3, 4 - Chapter 16 Class 11 Probability (Term 2)
Last updated at Dec. 3, 2020 by Teachoo
Last updated at Dec. 3, 2020 by Teachoo
Transcript
Ex 16.3, 4 A card is selected from a pack of 52 cards. How many points are there in the sample space? Since these are 52 cards these are 52 points in this sample space n(S) = 52 Ex 16.3, 4 (b) Calculate the probability that the card is an ace of spades. Here, n(s) = 52 There are 13 spade cards out of which only 1 is ace Let A be the event of ace spade card selected n(A) = 1 Probability that ace spade card is selected = P(A) = (๐๐ข๐๐๐๐ ๐๐ ๐๐๐ ๐ ๐๐๐๐ ๐๐๐๐)/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐๐ ) = (n(A))/(n(S)) = ๐/๐๐ Ex 16.3, 4 (c) Calculate the probability that the card is (i) an ace (ii) black card. (i) An ace There are 4 ace cards Let B be the event of getting an ace card n(B) = 4 Probability that ace card is selected from 52 cards = P(B) = (๐๐ข๐๐๐๐ ๐๐ ๐๐๐ ๐๐๐๐๐ )/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐๐ ) = (n(B))/(n(S)) = 4/52 = ๐/๐๐ (ii) black card There are 26 black card in a pack of 52 cards Let C be the event of selecting a black card n(C) = 26 Hence P(C) = (๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐๐ ๐๐๐๐๐ )/(๐๐๐ก๐๐ ๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐๐ ) = (n(C))/(n(S)) = 26/52 = ๐/๐
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