Ex 16.3
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Ex 16.3, 3 (i) Important
Ex 16.3, 3 (ii)
Ex 16.3, 3 (iii)
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Ex 16.3, 3 (v)
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Ex 16.3 ,5 Important You are here
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Ex 16.3, 12 (i)
Ex 16.3, 12 (ii) Important
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Ex 16.3
Last updated at Feb. 11, 2020 by Teachoo
Ex 16.3, 5 A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Find the probability that the sum of numbers that turn up is (i) 3 If the coin is tossed we get only 1 or 6 If a die is thrown we get 1, 2, 3, 4, 5, 6 Hence, S = {β("(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)," @" (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)" )} n(S) = 12 Let A be the event sum 3 Hence A = {(1, 2)} n(A) = 1 Probability of getting sum as 3 = P(A) = (n(A))/(n(S)) = π/ππ Ex 16.3, 5 A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Find the probability that the sum of numbers that turn up is (ii) 12 Let B be the event sum is 12. Hence B = {(6, 6)} n(B) = 1 Probability of getting sum as 12 = P(B) = (n(B))/(n(S)) = π/ππ