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Ex 16.3, 5 - A fair coin with 1 marked on one face, 6 on other

Ex 16.3 ,5 - Chapter 16 Class 11 Probability - Part 2

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Ex 16.3 ,5 - Chapter 16 Class 11 Probability - Part 3

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Ex 16.3, 5 A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Find the probability that the sum of numbers that turn up is (i) 3 If the coin is tossed we get only 1 or 6 If a die is thrown we get 1, 2, 3, 4, 5, 6 Hence, S = {โ–ˆ("(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)," @" (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)" )} n(S) = 12 Let A be the event sum 3 Hence A = {(1, 2)} n(A) = 1 Probability of getting sum as 3 = P(A) = (n(A))/(n(S)) = ๐Ÿ/๐Ÿ๐Ÿ Ex 16.3, 5 A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Find the probability that the sum of numbers that turn up is (ii) 12 Let B be the event sum is 12. Hence B = {(6, 6)} n(B) = 1 Probability of getting sum as 12 = P(B) = (n(B))/(n(S)) = ๐Ÿ/๐Ÿ๐Ÿ

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.