Ex 14.2, 3 (iv) - Chapter 14 Class 11 Probability
Last updated at July 19, 2026 by Teachoo
Ex 14.2
Ex 14.2
Last updated at July 19, 2026 by Teachoo
Transcript
Ex 14.2, 3 (iv) A number more than 6 will appear, There no number more than 6 Let D be the event that number more than 6 D = {} = š n(D) = 0 Probability of number more than 6 = (š(š·))/(š(š)) = 0/6 = 0