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Ex 16.3, 11 - In a lottery, person choses six different - Using combination

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  1. Chapter 16 Class 11 Probability
  2. Serial order wise
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Ex 16.3, 11 In a lottery, person choses six different natural numbers at random from 1 to 20, and if these six numbers match with the six numbers already fixed by the lottery committee, he wins the prize. What is the probability of winning the prize in the game? [Hint: order of the numbers is not important.] These are 20 natural number from 1 to 20 Total numbers = 20 Number to be chosen = 6 Number of ways choosing 6 natural number from 1 to 20 = 20C6 = 20!﷮6! 20 −6﷯!﷯ = 20!﷮6!14!﷯ = 38760 ways (Here we use combination as order of numbers is not important) So, n(S) = 38760 To win a prize, there is only 1 case when six numbers match Let A be the event of winning lottery So, n(A) = 1 Probability of winning lottery P(A) = 𝑛(𝐴)﷮𝑛(𝑆)﷯ = 𝟏﷮𝟑𝟖𝟕𝟔𝟎﷯

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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