Ex 16.3, 12 Check whether the following probabilities P(A) and P(B) are consistently defined P(A) = 0.5, P(B) = 0.7, P(A ∩ B) = 0.6 P(A) & P(B) are consistently defined if P(A ∩ B) < P(A) & P(A ∩ B) < P(B) P(A ∪ B) > P(A) & P(A ∪ B) > P(B) Given P(A) = 0.5, P(B) = 0.7, P(A ∩ B) = 0.6 Here, P(A ∩ B) > P(A). Hence, P(A) and P(B) are not consistently defined. Note: Here we use combination as order of numbers is not important So, n(S) = 38760 To win a prize, there is only 1 case when six numbers match Let A be the event of winning lottery So, n(A) = 1 Probability of winning lottery P(A) = (𝑛(𝐴))/(𝑛(𝑆)) = 𝟏/𝟑𝟖𝟕𝟔𝟎

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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