Ex 16.3, 16 - Chapter 16 Class 11 Probability
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 16.3, 16 Events E and F are such that P(not E or not F) = 0.25, State whether E and F are mutually exclusive. Given that P (not E or not F) = 0.25 P (E’ ∪ F’) = 0.25 P (E ∩ F)’ = 0.25 1 – P (E ∩ F) = 0.25 1 – 0.25 = P (E ∩ F) 0.75 = P (E ∩ F) P (E ∩ F) = 0.75 Since P (E ∩ F) ≠ 0 Since P (E ∩ F) ≠ 0 It means there is common elements between E and F Hence E and F are not mutually exclusive
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