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Ex 16.3, 3 (iii) - Chapter 16 Class 11 Probability (Term 2)
Last updated at March 16, 2023 by Teachoo
Ex 16.3
Ex 16.3, 1
Ex 16.3, 2
Ex 16.3, 3 (i) Important
Ex 16.3, 3 (ii)
Ex 16.3, 3 (iii) You are here
Ex 16.3, 3 (iv)
Ex 16.3, 3 (v)
Ex 16.3, 4 Important
Ex 16.3 ,5 Important
Ex 16.3, 6
Ex 16.3, 7 Important
Ex 16.3, 8 Important
Ex 16.3, 9
Ex 16.3, 10
Ex 16.3, 11 Important
Ex 16.3, 12 (i)
Ex 16.3, 12 (ii) Important
Ex 16.3, 13
Ex 16.3, 14 Important
Ex 16.3, 15 Important
Ex 16.3, 16 Important
Ex 16.3, 17
Ex 16.3, 18
Ex 16.3, 19
Ex 16.3, 20 Important
Ex 16.3, 21 Important
Transcript
Ex 16.3, 3 (iv) A number more than 6 will appear, There no number more than 6 Let D be the event that number more than 6 So, D = {} = ๐ โด n(D) = 0 Therefore, Probability of number more than 6 = (๐(๐ท))/(๐(๐)) = 0/6 = 0
