Ex 16.3, 3 (iii) - Chapter 16 Class 11 Probability (Term 2)
Last updated at Aug. 28, 2021 by Teachoo
Last updated at Aug. 28, 2021 by Teachoo
Transcript
Ex 16.3, 3 (iv) A number more than 6 will appear, There no number more than 6 Let D be the event that number more than 6 So, D = {} = ๐ โด n(D) = 0 Therefore, Probability of number more than 6 = (๐(๐ท))/(๐(๐)) = 0/6 = 0
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Ex 16.3, 3 (iii) You are here
Ex 16.3, 3 (iv)
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