Ex 14.2, 3 (iii) - Chapter 14 Class 11 Probability
Last updated at May 9, 2024 by Teachoo
Ex 14.2
Ex 14.2, 2
Ex 14.2, 3 (i) Important
Ex 14.2, 3 (ii)
Ex 14.2, 3 (iii) You are here
Ex 14.2, 3 (iv)
Ex 14.2, 3 (v)
Ex 14.2, 4 Important
Ex 14.2 ,5 Important
Ex 14.2, 6
Ex 14.2, 7 Important
Ex 14.2, 8 Important
Ex 14.2, 9
Ex 14.2, 10
Ex 14.2, 11 Important
Ex 14.2, 12 (i)
Ex 14.2, 12 (ii) Important
Ex 14.2, 13
Ex 14.2, 14 Important
Ex 14.2, 15 Important
Ex 14.2, 16 Important
Ex 14.2, 17
Ex 14.2, 18
Ex 14.2, 19
Ex 14.2, 20 Important
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Ex 14.2
Last updated at May 9, 2024 by Teachoo
Ex 14.2, 3 (iv) A number more than 6 will appear, There no number more than 6 Let D be the event that number more than 6 So, D = {} = 𝜙 ∴ n(D) = 0 Therefore, Probability of number more than 6 = (𝑛(𝐷))/(𝑛(𝑆)) = 0/6 = 0