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Last updated at Feb. 11, 2020 by Teachoo
Transcript
Ex 16.3, 15 If E & F are events such that P(E) = 1/4 , P(F) = 1/2 and P(E and F) = 1/8, find: (i) P(E or F) P(E and F) = P(E ∩ F) = 1/8 We need to find P(E or F) = P(E ∪ F) We know that P(E ∪ F) = P(E) + P(F) – P(E ∩ F) Putting values P(E ∪ F) = 1/4 + 1/2 – 1/8 = (2 + 4 − 1)/8 = (6 − 1)/8 = 𝟓/𝟖 Ex 16.3, 15 If E & F are events such that P(E) = 1/4 , P(F) = 1/2 and P(E and F) = 1/8, find: (ii) P(not E and not F). P (not E and not F) = P(E’ ∩ F’) = P (E ∪ F)’ = 1 – P (E ∪ F) = 1 – 5/8 = (8 − 5)/8 = 𝟑/𝟖 Demorgan’s law █("If (A’" ∩"B’) = (A " ∪" B)’ " @"or (A’ " ∪" B’) = (A " ∩" B)’" )
Ex 16.3
Ex 16.3, 2
Ex 16.3, 3 (i) Important
Ex 16.3, 3 (ii)
Ex 16.3, 3 (iii)
Ex 16.3, 3 (iv)
Ex 16.3, 3 (v)
Ex 16.3, 4 Important
Ex 16.3 ,5 Important
Ex 16.3, 6
Ex 16.3, 7 Important
Ex 16.3, 8 Important
Ex 16.3, 9
Ex 16.3, 10
Ex 16.3, 11 Important
Ex 16.3, 12 (i)
Ex 16.3, 12 (ii) Important
Ex 16.3, 13
Ex 16.3, 14 Important
Ex 16.3, 15 Important You are here
Ex 16.3, 16 Important
Ex 16.3, 17
Ex 16.3, 18
Ex 16.3, 19
Ex 16.3, 20 Important
Ex 16.3, 21 Important
Ex 16.3
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