Ex 16.3, 15 - Chapter 16 Class 11 Probability
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 16.3, 15 If E and F are events such that P(E) = 1 4 , P(F) = 1 2 and P(E and F) = 1 8 , find:(i) P(E or F) P(E and F) = P(E F) = 1 8 We need to find P(E or F) = P(E F) We know that P(E F) = P(E) + P(F) P(E F) Putting values P(E F) = 1 4 + 1 2 1 8 = 2 + 4 1 8 = 6 1 8 = Ex16.3, 15 If E and F are events such that P(E) = 1 4 , P(F) = 1 2 and P(E and F) = 1 8 , find: (ii) P(not E and not F). P (not E and not F) = P(E F ) = P (E F) = 1 P (E F) = 1 5 8 = 8 5 8 =
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