Ex 16.3, 3 - A die is thrown, find probability (i) A prime number - Ex 16.3

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  1. Chapter 16 Class 11 Probability
  2. Serial order wise
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Ex 16.3, 3 A die is thrown, find the probability of following events: A prime number will appear, When a die is thrown, Sample space = S = {1, 2, 3, 4, 5, 6} Hence, n(S) = 6 Prime numbers between 1 to 6 are 2, 3 and 5 Let A be the event of that prime number appear Hence n(A) = 3 Probability of prime number = n(A) n(s) = 3 6 = Ex 16.3, 3 (ii) A number greater than or equal to 3 will appear, Number greater than or equal to 3 are 3, 4, 5, 6 Let B be the event that greater than or equal to 3 B = {3, 4, 5, 6} n(B) = 4 Probability of number greater than or equal 3 = ( ) ( ) = 4 6 = Ex 16.3, 3 (iii) A number less than or equal to one will appear, There is one number less than or equal to or less than 1 = 1 Let C be the event number less than or equal to 1 So, C = {1} n(C) = 1 Probability of number equal to or less than 1 = ( ) ( ) = Ex 16.3, 3 (iv) A number more than 6 will appear, There no number more than 6 Let D be the event that number more than 6 D = {} = n(D) = 0 Probability of number more than 6 = ( ) ( ) = 0 6 = 0 Ex 16.3, 3 (v) A number less than 6 will appear. Numbers less than 6 are 1, 2, 3, 4, 5 Let E be the event number less than 6 E = {1, 2, 3, 4, 5} n(E) = 5 Probability of number less than 6 = ( ) ( ) =

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