Ex 13.2, 3 - Chapter 13 Class 11 Limits and Derivatives (Term 1 and Term 2)
Last updated at Nov. 30, 2019 by Teachoo
Transcript
Ex 13.2, 3 Find the derivative of 99x at x = 100 Let f (x) = x We need to find derivative of f(x) at x = 100 i.e. fβ (100) We know that fβ (x) = (πππ)β¬(ββ0)β‘γ(π(π₯ + β) β π (π₯))/βγ Here, f(x) = 99x So, f(x + h) = 99(x + h) = 99x + 99h Putting values fβ (x) = limβ¬(hβ0)β‘γ((99π₯ +99β) β 99π₯)/βγ = limβ¬(hβ0)β‘γ(99π₯ +99β β 99π₯)/βγ = limβ¬(hβ0)β‘γ99β/βγ = limβ¬(hβ0) 99 = 99 Hence, fβ(x) = 99 Putting x = 100 fβ(100) = 99 So, derivative of 99x at x = 100 is 99
Ex 13.2 (Term 2)
Ex 13.2, 1
Ex 13.2, 2
Ex 13.2, 3 You are here
Ex 13.2, 4 (i) Important
Ex 13.2, 4 (ii)
Ex 13.2, 4 (iii) Important
Ex 13.2, 4 (iv)
Ex 13.2, 5
Ex 13.2, 6
Ex 13.2, 7 (i) Important
Ex 13.2, 7 (ii)
Ex 13.2, 7 (iii) Important
Ex 13.2, 8
Ex 13.2, 9 (i)
Ex 13.2, 9 (ii) Important
Ex 13.2, 9 (iii)
Ex 13.2, 9 (iv) Important
Ex 13.2, 9 (v)
Ex 13.2, 9 (vi)
Ex 13.2, 10 Important
Ex 13.2, 11 (i)
Ex 13.2, 11 (ii) Important
Ex 13.2, 11 (iii) Important
Ex 13.2, 11 (iv)
Ex 13.2, 11 (v) Important
Ex 13.2, 11 (vi)
Ex 13.2, 11 (vii) Important
Chapter 13 Class 11 Limits and Derivatives (Term 1 and Term 2)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.