Ex 12.2, 11 - Find the derivative of sec x - Teachoo - Ex 12.2 - Ex 12.2

part 2 - Ex 12.2, 11 (ii) - Ex 12.2 - Serial order wise - Chapter 12 Class 11 Limits and Derivatives
part 3 - Ex 12.2, 11 (ii) - Ex 12.2 - Serial order wise - Chapter 12 Class 11 Limits and Derivatives

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Ex 12.2, 11 Find the derivative of the following functions: (ii) sec x Let f (x) = sec x f(x) = 1/cos⁑π‘₯ Let u = 1 & v = cos x So, f(x) = 𝑒/𝑣 ∴ f’(x) = (𝑒/𝑣)^β€² Using quotient rule f’(x) = (𝑒^β€² 𝑣 βˆ’ 𝑣^β€² 𝑒)/𝑣^2 Finding u’ & v’ u = 1 u’ = 0 & v = cos x v’ = – sin x Now, f’(x) = (𝑒^β€² 𝑣 βˆ’ 𝑣^β€² 𝑒)/𝑣^2 = (0(cos⁑〖π‘₯) βˆ’ (βˆ’sin⁑〖π‘₯) (1)γ€— γ€—)/(γ€–π‘π‘œπ‘ γ€—^2 π‘₯) (Derivative of constant is 0) (Derivative of cos x = – sin x) = (0 +γ€– sin〗⁑π‘₯)/(γ€–π‘π‘œπ‘ γ€—^2 π‘₯) = γ€– sin〗⁑π‘₯/(γ€–π‘π‘œπ‘ γ€—^2 π‘₯) = γ€– sin〗⁑π‘₯/cos⁑π‘₯ . 1/cos⁑π‘₯ = tan x . sec x Hence f’(x) = tan x . sec x Using tan ΞΈ = sinβ‘πœƒ/π‘π‘œπ‘ πœƒ & 1/cosβ‘πœƒ = sec ΞΈ

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