This question is similar to Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Ex 3.1

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https://www.teachoo.com/1512/499/Ex-3.2--7---Draw-graphs-of-x---y---1--0-and-3x---2y---12--0/category/Ex-3.2/

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Solve equations graphically: 2š‘„ + š‘¦ = 6, 2š‘„ – š‘¦ – 2 = 0. Find area - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard

part 2 - Question 31 (B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 31 (B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10 part 4 - Question 31 (B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10 part 5 - Question 31 (B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 31 (Choice B) Solve the following system of equations graphically: 2š‘„ + š‘¦ = 6, 2š‘„ – š‘¦ – 2 = 0. Find the area of the triangle so formed by two lines and š‘„ - axis.Our equations are 2x + y = 6 2x – y = 2 For Equation (1) 2x + y = 6 Putting y = 0 2x + 2(0) = 6 2x = 6 x = 6/2 x = 3 So, x = 3, y = 0 is a solution i.e. (2, 0) is a solution Putting x = 0 2(0) + y = 6 0 + y = 6 y = 6 So, x = 0, y = 6 is a solution i.e. (0, 6) is a solution For Equation (2) 2x – y = 2 Putting x = 0 2(0) āˆ’ y = 2 0 āˆ’ y = 2 āˆ’y = 2 y = –2 So, x = 0, y = –2 is a solution i.e. (0, –2) is a solution Putting y = 0 2x āˆ’ 0 = 2 2x = 2 x = 2/2 x = 1 So, x = 1, y = 0 is a solution i.e. (1, 0) is a solution We will plot both equations on the graph Area of Required triangle Triangle has Base = 2 units Height = 2 units Thus, Area of triangle = 1/2 Ɨ Base Ɨ Height = 1/2 Ɨ 2 Ɨ 2 = 2 square units

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