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If the lines given by 3x +2ky =2 and 2x+5y +1=0 are not parallel, then - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard

part 2 - Question 3 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 3 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 3 If the lines given by 3𝑥+2𝑘𝑦=2 and 2𝑥+5𝑦+1=0 are not parallel, then k has to be (A) 15/4 (B) ≠15/4 (C) any rational number (D) any rational number having 4 as denominator3x + 2ky − 2 = 0 Comparing with a1x + b1y + c1 = 0 ∴ a1 = 3 , b1 = 2k , c1 = −2 2x + 5y + 1 = 0 Comparing with a2x + b2y + c2 = 0 ∴ a2 = 2 , b2 = 5, c2 = 1 𝑎1/𝑎2 = 3/2 𝑏1/𝑏2 = 2𝑘/5 𝑐1/𝑐2 = (−2)/1 𝑐1/𝑐2 = −2 Since the lines are not parallel 𝒂𝟏/𝒂𝟐 ≠ 𝒃𝟏/𝒃𝟐 3/2≠2𝑘/5 Therefore, a1 = 3 , b1 = 2k , c1 = −2 & a2 = 2 , b2 = 5, c2 = 1 3/2 × 5/2 ≠ k k ≠ 𝟏𝟓/𝟒 So, the correct answer is (b)

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