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Find the zeroes of the quadratic polynomial 2š‘„2 – (1 + 2√2) š‘„ + √2 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard

part 2 - Question 28 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 28 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 28 Find the zeroes of the quadratic polynomial 2š‘„2 – (1 + 2√2) š‘„ + √2 and verify the relationship between the zeroes and coefficients of the polynomial.Let p(x) = 2š‘„2 – (1 + 2√2) š‘„ + √2 Zero of the polynomial is the value of x where p(x) = 0 Putting p(x) = 0 2š‘„2 – (1 + 2√2) š‘„ + √2 = 0 We find roots using splitting the middle term method 2x2 – x – 2āˆššŸ x + āˆššŸ = 0 x(2x – 1) – √2(2x – 1) = 0 Splitting the middle term method We need to find two numbers where Sum = 1 + 2√2 Product = 2 Ɨ √2 = 2 √2 (x – āˆššŸ)(2x āˆ’ 1) = 0 Thus, our roots are x = āˆššŸ, and x =šŸ/šŸ Verifying relationship b/w zeroes and coefficients p(x) = 2š‘„2 – (1 + 2√2) š‘„ + √2 Comparing with ax2 + bx + c a = 2 , b = –(1 + 2āˆššŸ), c = āˆššŸ We have to verify Sum of zeroes = āˆ’ (š¶š‘œš‘’š‘“š‘“š‘–š‘š‘–š‘’š‘›š‘” š‘œš‘“ š‘„)/(š¶š‘œš‘’š‘“š‘“š‘–š‘š‘–š‘’š‘›š‘” š‘œš‘“ š‘„2) i.e. α + β = – š’ƒ/š’‚ Since, L.H.S = R.H.S Hence relationship between zeroes & coefficient is verified Product of zeroes = (š¶š‘œš‘›š‘ š‘”š‘Žš‘›š‘” š‘”š‘’š‘Ÿš‘š)/(š¶š‘œš‘’š‘“š‘“š‘–š‘š‘–š‘’š‘›š‘” š‘œš‘“ š‘„2) i.e. α Ɨ β = š’„/š’‚

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