Question 38 (iii) (Choice B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at July 25, 2026 by Teachoo

[SQP] If Shreya moves to a point which is at a distance of 41/√3 from - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard

part 2 - Question 38 (iii) (Choice B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

Question 38 (iii) - Choice (B) If Shreya moves to a point which is at a distance of 41/√3 m from the India Gate, then find the angle of elevation made by her eye to the top of India Gate.Now, Shreya is standing at a distance of 41/√3 m away So, YB = XC = 𝟒𝟏/√𝟑 m In right angle triangle AXC, tan X = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝑋)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝑋) tan X = AC/XC tan X = 41/(41/√3) tan X = 41 ×√3/41 tan X = √3 Thus, ∠ X = 60° So, required angle of elevation is 60°

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