Question 38 (ii) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at July 25, 2026 by Teachoo

If Shreya observes the angle of elevation from her eye to the top - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard

part 2 - Question 38 (ii) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

Question 38 (ii) If Shreya observes the angle of elevation from her eye to the top of India Gate to be 60^∘, then how far is the she standing from the base of the India Gate? Now, we need to find BN By symmetry BN = MC In right angle triangle AMC, tan M = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝑀)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝑀) tan 60° = AC/MC √3 = 41/𝑀𝐶 MC = 𝟒𝟏/√𝟑 Multiplying √3 in both numerator and denominator MC = 41/√3 × √3/√3 MC = (𝟒𝟏 √𝟑)/𝟑 m ∴ Shreya is standing at a distance of (𝟒𝟏 √𝟑)/𝟑 m

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