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[SQP] If the mode of the distribution is 55, then find the value of x - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard

part 2 - Question 35 (A) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 35 (A) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10 part 4 - Question 35 (A) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 35 (Choice A) If the mode of the following distribution is 55, then find the value of š‘„. Hence, find the mean.Given Mode = 55 ∓ Modal class is 45 āˆ’ 60 Mode = l + (š’‡šŸ āˆ’š’‡šŸŽ)/(šŸš’‡šŸ āˆ’ š’‡šŸŽ āˆ’ š’‡šŸ) Ɨ h where l = lower limit of modal class h = class-interval f1 = frequency of the modal class f0 = frequency of the class before modal class f2 = frequency of the class after modal class Now, Mode = l + (š’‡šŸ āˆ’š’‡šŸŽ)/(šŸš’‡šŸ āˆ’ š’‡šŸŽ āˆ’ š’‡šŸ) Ɨ h 55 = 45 + (15 āˆ’ š‘„)/(2(15) āˆ’ š‘„ āˆ’ 10) Ɨ 15 55 āˆ’ 45 = (15 āˆ’ š‘„)/(30 āˆ’ š‘„ āˆ’ 10) Ɨ 15 10 = (15 āˆ’ š‘„)/(20 āˆ’ š‘„) Ɨ 15 10(20 āˆ’ x) = (15 āˆ’ x) Ɨ 15 200 āˆ’ 10x = 225 āˆ’ 15x 15x āˆ’ 10x = 225 – 200 5x = 25 x = 25/5 x = 5 Thus, our table looks like Now, finding mean Mean(š‘„ Ģ…) = (āˆ‘ā–’š‘“š‘–š‘„š‘–)/(āˆ‘ā–’š‘“š‘–) š‘„ Ģ… = 2872.5/59 š’™ Ģ… = 48.68

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