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[SQP] If the mode of the distribution is 55, then find the value of x - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard

part 2 - Question 35 (A) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 35 (A) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10 part 4 - Question 35 (A) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 35 (Choice A) If the mode of the following distribution is 55, then find the value of 𝑥. Hence, find the mean.Given Mode = 55 ∴ Modal class is 45 − 60 Mode = l + (𝒇𝟏 −𝒇𝟎)/(𝟐𝒇𝟏 − 𝒇𝟎 − 𝒇𝟐) × h where l = lower limit of modal class h = class-interval f1 = frequency of the modal class f0 = frequency of the class before modal class f2 = frequency of the class after modal class Now, Mode = l + (𝒇𝟏 −𝒇𝟎)/(𝟐𝒇𝟏 − 𝒇𝟎 − 𝒇𝟐) × h 55 = 45 + (15 − 𝑥)/(2(15) − 𝑥 − 10) × 15 55 − 45 = (15 − 𝑥)/(30 − 𝑥 − 10) × 15 10 = (15 − 𝑥)/(20 − 𝑥) × 15 10(20 − x) = (15 − x) × 15 200 − 10x = 225 − 15x 15x − 10x = 225 – 200 5x = 25 x = 25/5 x = 5 Thus, our table looks like Now, finding mean Mean(𝑥 ̅) = (∑▒𝑓𝑖𝑥𝑖)/(∑▒𝑓𝑖) 𝑥 ̅ = 2872.5/59 𝒙 ̅ = 48.68

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