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Ex 3.2, 7 - Draw graphs of x - y + 1 = 0 and 3x + 2y - 12 = 0

Ex 3.2, 7 - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 2
Ex 3.2, 7 - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 3
Ex 3.2, 7 - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 4
Ex 3.2, 7 - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 5

 

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Ex 3.2, 7 Draw the graphs of the equations x – y + 1 = 0 and 3x+ 2y – 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region. Our equations are x – y = −1 3x + 2y = 12 For Equation (1) x − y = −1 Putting x = 0 0 − y = −1 −y = −1 y = 1 So, x = 0, y = 1 is a solution i.e. (0, 1) is a solution Putting y = 0 x − 0 = −1 x = −1 So, x = −1, y = 0 is a solution i.e. (−1, 0) is a solution For Equation (2) 3x + 2y = 12 Putting x = 0 3(0) + 2y = 12 2y = 12 y = 12/2 y = 6 So, x = 0, y = 6 is a solution i.e. (0, 6) is a solution Putting y = 0 3x + 2(0) = 12 3x = 12 x = 12/3 x = 4 So, x = 4, y = 0 is a solution i.e. (4, 0) is a solution We will plot both equations on the graph Therefore, the Required triangle is the triangle with vertices (2, 3), (–1, 0) & (4, 0)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.