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Ex 3.2, 5 - Half the perimeter of a rectangular garden - Ex 3.2

Ex 3.2, 5 - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 2
Ex 3.2, 5 - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 3 Ex 3.2, 5 - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 4 Ex 3.2, 5 - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 5 Ex 3.2, 5 - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 6


Transcript

Ex 3.2, 5 Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden. Let Length of Rectangular Garden be x meters & Breadth of Rectangular Garden be y meters Given Half perimeter of rectangular garden is 36 m 1/2 × 2(Length + Breadth)= 36 x + y = 36 Also, Length is 4 m more than its width Length = 4 + Breadth x = 4 + y x – y = 4 Now, Solving these equations on graph x + y = 36 ...(1) x – y = 4 …(2) For Equation (1) x + y = 36 Putting x = 12 12 + y = 36 y = 36 − 12 y = 24 So, x = 12, y = 24 is a solution i.e. (12, 24) is a solution Putting y = 16 x + 16 = 36 x = 36 − 16 x = 20 So, x = 20, y = 16 is a solution i.e. (20, 16) is a solution For Equation (2) x − y = 4 Putting y = 0 x − 0 = 4 x = 4 So, x = 4, y = 0 is a solution i.e. (4, 0) is a solution Putting x = 0 0 − y = 4 −y = 4 y = −4 So, x = 0, y = −4 is a solution i.e. (0, −4) is a solution We will plot both equations on the graph The equations intersect at (20, 16) So, the Solution of our equations is (20, 16) Therefore Length of garden = x = 20 m Breadth of garden = y = 16 m

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.