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Ex 3.2, 5 - Half the perimeter of a rectangular garden - Ex 3.2

 

  1. Chapter 3 Class 10 Pair of Linear Equations in Two Variables
  2. Serial order wise
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Ex 3.2, 5 Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden. Let the length of rectangular garden be x metres. & Let the breadth of rectangular garden be y. Given half perimeter of rectangular garden is 36 m 1/2 {2(Length + breadth) }= 36 or (x + y) = 36 x + y – 36 = 0 Also, Length is 4 m more than its width (Length )= 4 + (Breadth) or x = 4 + (y) x – y – 4 = 0 Now, plotting equations x + y – 36 = 0 ...(1) x – y – 4 = 0 …(2) Solving (1) x + y – 36 = 0 y = 36 – x Solving (2) x − y – 4 = 0 y = x − 4 The equations intersect at (20,16) So, the solutions of our equation is (20,16) Length of garden = x = 20 m Breadth of garden = y = 16 m

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