


Get live Maths 1-on-1 Classs - Class 6 to 12
Examples
Example 2
Example 3
Example 4 Important You are here
Example 5
Example 6 Important
Example 7
Example 8
Example 9
Example 10 Important
Example 11 Important
Example 12
Example 13 Important
Example 14 Important
Example 15
Example 16 Important Deleted for CBSE Board 2023 Exams
Example 17 Deleted for CBSE Board 2023 Exams
Example 18 Important Deleted for CBSE Board 2023 Exams
Example 19 Important Deleted for CBSE Board 2023 Exams
Last updated at March 22, 2023 by Teachoo
Example 4 Check graphically, whether the pair of equations x + 3y = 6 and 2x – 3y= 12 is consistent. If so, solve them graphically. Let equations be x + 3y = 6 2x – 3y = 12 Let’s draw their graphs For Equation (1) x + 3y = 6 Putting x = 0 0 + 3y = 6 3y = 6 y = 6/3 y = 2 So, x = 0, y = 2 is a solution i.e. (0, 2) is a solution Putting y = 0 x + 3(0) = 6 x + 0 = 6 x = 6 So, x = 6, y = 0 is a solution i.e. (6, 0) is a solution For Equation (2) 2x − 3y = 12 Putting x = 0 2(0) − 3y = 12 0 − 3y = 12 −3y = 12 y = 12/(−3) y = −4 So, x = 0, y = −4 is a solution i.e. (0, −4) is a solution Putting y = 0 2x − 3(0) = 12 2x = 12 x = 12/2 x = 6 So, x = 6, y = 0 is a solution i.e. (6, 0) is a solution We will plot both equations on the graph Since the lines intersect, the given equations are consistent And solution is (6, 0)