Learn all Concepts of Chapter 3 Class 10 (with VIDEOS). Check - Linear Equations in 2 Variables - Class 10

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  1. Chapter 3 Class 10 Pair of Linear Equations in Two Variables
  2. Serial order wise

Transcript

Example 18 Solve the following pair of equations by reducing them to a pair of linear equations : 5/(๐‘ฅ โˆ’1) + 1/(๐‘ฆ โˆ’2) = 2 6/(๐‘ฅ โˆ’1) โ€“ 3/(๐‘ฆ โˆ’2) = 1 5/(๐‘ฅ โˆ’ 1) + 1/(๐‘ฆ โˆ’ 2) = 2 6/(๐‘ฅ โˆ’ 1) โ€“ 3/(๐‘ฆ โˆ’ 2) = 1 Let 1/(๐‘ฅ โˆ’ 1) = u 1/(๐‘ฆ โˆ’ 2) = v So, our equations become 5u + v = 2 6u โ€“ 3v = 1 Thus, our equations are 5u + v = 2 โ€ฆ(3) 6u โ€“ 3v = 1 โ€ฆ(4) From (3) 5u + v = 2 v = 2 โ€“ 5u Putting value of v in (4) 6u โ€“ 3v = 1 6u โ€“ 3(2 โ€“ 5u) = 1 6u โ€“ 6 + 15u = 1 6u + 15u = 1 + 6 21u = 7 u = 7/21 u = 1/3 Putting u = 1/3 in equation (3) 5u + v = 2 5(1/3) + v = 2 5/3 + v = 2 v = 2 โ€“ 5/3 v = (2(3) โˆ’ 5)/3 v = (6 โˆ’ 5)/3 v = ๐Ÿ/๐Ÿ‘ Hence, u = 1/3 & v = 1/3 But we need to find x & y u = ๐Ÿ/(๐’™ โˆ’ ๐Ÿ) 1/3 = 1/(๐‘ฅ โˆ’ 1) x โ€“ 1 = 3 x = 3 + 1 x = 4 v = ๐Ÿ/(๐’š โˆ’ ๐Ÿ) 1/3 = 1/(๐‘ฆ โˆ’2) y โ€“ 2 = 3 y = 3 + 2 y = 5 So, x = 4, y = 5 is the solution of our equations

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.