Learn all Concepts of Chapter 3 Class 10 (with VIDEOS). Check - Linear Equations in 2 Variables - Class 10

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  1. Chapter 3 Class 10 Pair of Linear Equations in Two Variables
  2. Serial order wise

Transcript

Example 17 Solve the pair of equations: 2/๐‘ฅ+ 3/๐‘ฆ=13 5/๐‘ฅโˆ’4/๐‘ฆ=โˆ’2 2/๐‘ฅ+ 3/๐‘ฆ=13 5/๐‘ฅโˆ’4/๐‘ฆ=โˆ’2 Let 1/๐‘ฅ = u 1/๐‘ฆ = v So, our equations become 2u + 3v = 13 5u โ€“ 4v = โ€“2 Hence, our equations are 2u + 3v = 13 โ€ฆ(3) 5u โ€“ 4v = โ€“ 2 โ€ฆ(4) From (3) 2u + 3v = 13 2u = 13 โ€“ 3V u = (13 โˆ’ 3๐‘ฃ)/2 Putting value of u (4) 5u โ€“ 4v = - 2 5((13 โˆ’ 3๐‘ฃ)/2)โˆ’4๐‘ฃ=โˆ’2 Multiplying 2 both sides 2 ร— 5((13 โˆ’ 3๐‘ฃ)/2)โˆ’"2 ร—" 4๐‘ฃ="2 ร—"โˆ’2 5(13 โ€“ 3v) โ€“ 8v = โ€“4 65 โ€“ 15v โ€“ 8v = โ€“4 โ€“ 15v โ€“ 8v = โ€“ 4 โ€“ 65 โ€“ 23v = โ€“ 69 v = (โˆ’69)/(โˆ’23) v = 3 Putting v = 3 in (3) 2u + 3v = 13 2u + 3(3) = 13 2u + 9 = 13 2u = 13 โ€“ 9 2u = 4 u = 4/2 u = 2 Hence, u = 2, v = 3 is the solution But we have to find x & y u = ๐Ÿ/๐’™ 2 = 1/๐‘ฅ x = ๐Ÿ/๐Ÿ v = ๐Ÿ/๐’š 3 = 1/๐‘ฆ y = ๐Ÿ/๐Ÿ‘ Hence, x = 1/2 , y = 1/3 is the solution of the given equation

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.