Last updated at July 20, 2018 by Teachoo

Transcript

Ex 3.1,1 Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” Represent this situation algebraically and graphically. Let the current age of Aftab be x years. & Let the current age of Aftab’s daughter be y years. Seven years ago, Age of Aftab = x − 7 Age of Aftab’s daughter = y − 5 Aftab was seven times as old as Aftab’s daughter (x – 7) = 7(y – 7 ) (x – 7) = 7y – 49 x – 7 – 7y + 49 = 0 x – 7y + 42 = 0 Three years later, Age of Aftab = x + 3 Age of Aftab’s daughter = y + 3 Aftab will be three times as Aftab’s daughter (x + 3) = 3(y + 3 ) (x + 3) = 3y + 9 x + 3 – 3y - 9 = 0 x – 3y − 6 = 0 Now, plotting equations x – 7y + 42 = 0 ...(1) x – 3y − 6 = 0 …(2) Solving (1) x – 7y + 42 = 0 7y = x + 42 y = (𝑥 + 42)/7 Solving equation (2) , x – 3y - 6 = 0 3y = x - 6 y = (𝑥 − 6)/3

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.