This question is similar to Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Ex 3.1
Please check the question here
CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard
CBSE Class 10 Sample Paper for 2026 Boards - Maths Standard
Last updated at Aug. 25, 2025 by Teachoo
This question is similar to Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Ex 3.1
Please check the question here
Transcript
Question 31 (Choice B) Solve the following system of equations graphically: 2𝑥 + 𝑦 = 6, 2𝑥 – 𝑦 – 2 = 0. Find the area of the triangle so formed by two lines and 𝑥 - axis.Our equations are 2x + y = 6 2x – y = 2 For Equation (1) 2x + y = 6 Putting y = 0 2x + 2(0) = 6 2x = 6 x = 6/2 x = 3 So, x = 3, y = 0 is a solution i.e. (2, 0) is a solution Putting x = 0 2(0) + y = 6 0 + y = 6 y = 6 So, x = 0, y = 6 is a solution i.e. (0, 6) is a solution For Equation (2) 2x – y = 2 Putting x = 0 2(0) − y = 2 0 − y = 2 −y = 2 y = –2 So, x = 0, y = –2 is a solution i.e. (0, –2) is a solution Putting y = 0 2x − 0 = 2 2x = 2 x = 2/2 x = 1 So, x = 1, y = 0 is a solution i.e. (1, 0) is a solution We will plot both equations on the graph Area of Required triangle Triangle has Base = 2 units Height = 2 units Thus, Area of triangle = 1/2 × Base × Height = 1/2 × 2 × 2 = 2 square units