This question is similar to Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Ex 3.1

Please check the question here

https://www.teachoo.com/1512/499/Ex-3.2--7---Draw-graphs-of-x---y---1--0-and-3x---2y---12--0/category/Ex-3.2/

 

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Question 31 (Choice B) Solve the following system of equations graphically: 2𝑥 + 𝑦 = 6, 2𝑥 – 𝑦 – 2 = 0. Find the area of the triangle so formed by two lines and 𝑥 - axis.Our equations are 2x + y = 6 2x – y = 2 For Equation (1) 2x + y = 6 Putting y = 0 2x + 2(0) = 6 2x = 6 x = 6/2 x = 3 So, x = 3, y = 0 is a solution i.e. (2, 0) is a solution Putting x = 0 2(0) + y = 6 0 + y = 6 y = 6 So, x = 0, y = 6 is a solution i.e. (0, 6) is a solution For Equation (2) 2x – y = 2 Putting x = 0 2(0) − y = 2 0 − y = 2 −y = 2 y = –2 So, x = 0, y = –2 is a solution i.e. (0, –2) is a solution Putting y = 0 2x − 0 = 2 2x = 2 x = 2/2 x = 1 So, x = 1, y = 0 is a solution i.e. (1, 0) is a solution We will plot both equations on the graph Area of Required triangle Triangle has Base = 2 units Height = 2 units Thus, Area of triangle = 1/2 × Base × Height = 1/2 × 2 × 2 = 2 square units

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo