Ex 14.2, 3 (iii) - Chapter 14 Class 11 Probability
Last updated at Dec. 16, 2024 by Teachoo
Ex 14.2
Ex 14.2
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Ex 14.2, 3 (iv) A number more than 6 will appear, There no number more than 6 Let D be the event that number more than 6 So, D = {} = 𝜙 ∴ n(D) = 0 Therefore, Probability of number more than 6 = (𝑛(𝐷))/(𝑛(𝑆)) = 0/6 = 0