Find the general solution of the following differential equation: 𝑥 𝑑𝑦 − (𝑦 + 2𝑥 2 )𝑑𝑥 = 0

 

Find general solution of differential equation: xdy - (y + 2x^2)dx = 0

Question 35 - CBSE Class 12 Sample Paper for 2021 Boards - Part 2
Question 35 - CBSE Class 12 Sample Paper for 2021 Boards - Part 3

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Question 35 Find the general solution of the following differential equation: 𝑥 𝑑𝑦 − (𝑦 + 2𝑥2 )𝑑𝑥 = 0 Given 𝑥 𝑑𝑦 = (𝑦 + 2𝑥2 )𝑑𝑥 𝑑𝑦/𝑑𝑥=(𝑦 + 2𝑥^2)/𝑥 𝑑𝑦/𝑑𝑥=𝑦/𝑥+2𝑥 𝒅𝒚/𝒅𝒙−𝒚/𝒙=𝟐𝒙 Comparing with 𝒅𝒚/𝒅𝒙 + Py = Q ∴ P = (−1)/𝑥 and Q = 2x Find integrating factor IF IF = e^∫1▒𝑃𝑑𝑥 IF = 𝑒^∫1▒〖(−1)/𝑥 𝑑𝑥〗 IF = 𝑒^(−log⁡𝑥 ) IF = 𝑒^log⁡〖(𝑥)^(−1) 〗 IF = 𝑒^〖log 〗⁡〖1/𝑥〗 IF = 𝟏/𝒙 Solution of the equation y × I.F = ∫1▒〖𝑸 × 𝑰.𝑭.𝒅𝒙+𝒄 〗 Putting values, 𝑦 ×1/𝑥 = ∫1▒〖2𝑥 ×1/𝑥 𝑑𝑥〗+𝐶 𝑦/𝑥 = ∫1▒2𝑑𝑥+𝐶 𝑦/𝑥 = 2𝑥+𝐶 𝒚 = 𝟐𝒙^𝟐+𝑪𝒙

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