Check sibling questions

Find the value of sin -1  [sin(13π/7)]

 


Transcript

Question 21 (Choice 1) Find the value of 〖𝑠𝑖𝑛〗^(βˆ’1) [𝑠𝑖𝑛(13πœ‹/7)]. Let y = sinβˆ’1 ("sin " 13Ο€/7) sin y = sin (13Ο€/7) sin y = sin (334Β°) But, Range of sinβˆ’1 is [(βˆ’Ο€)/2, Ο€/2] i.e. [βˆ’90Β° ,90Β° ] Hence, y = 334Β° not possible Now, sin y = sin (13Ο€/7) sin y = sin (πŸπ…βˆ’π›‘/πŸ•) sin y = βˆ’ sin (𝛑/πŸ•) sin y = sin ((βˆ’π›‘)/πŸ•) Hence, y = (βˆ’π…)/πŸ• Which is in the range of sin-1 i.e. [(βˆ’Ο€)/2, Ο€/2] Hence, sin-1("sin " 13Ο€/7) = y = (βˆ’π…)/πŸ•

  1. Class 12
  2. Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo