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The scalar projection of the vector 3i ฬ‚-j ฬ‚-2k ฬ‚ ๐‘œ๐‘› ๐‘กโ„Ž๐‘’ ๐‘ฃ๐‘’๐‘๐‘ก๐‘œ๐‘Ÿ i ฬ‚+2j ฬ‚-3k ฬ‚ is

(a) 7/โˆš14 ย 

(b) 7/14 ย 

(c) 6/13 ย 

(d) 7/2

ย 

ย 


Transcript

Question 8 The scalar projection of the vector 3๐‘– ฬ‚โˆ’๐‘— ฬ‚โˆ’2๐‘˜ ฬ‚ ๐‘œ๐‘› ๐‘กโ„Ž๐‘’ ๐‘ฃ๐‘’๐‘๐‘ก๐‘œ๐‘Ÿ ๐‘– ฬ‚+2๐‘— ฬ‚โˆ’3๐‘˜ ฬ‚ is (a) 7/โˆš14 (b) 7/14 (c) 6/13 (d) 7/2 Let a = 3๐‘– ฬ‚ โˆ’ ๐‘— ฬ‚ โˆ’ 2๐‘˜ ฬ‚ and b = ๐‘– ฬ‚ + 2๐‘— ฬ‚ โˆ’ 3๐‘˜ ฬ‚ We need to find Projection of ๐‘Ž โƒ— on ๐‘ โƒ— We know that Projection of ๐‘Ž โƒ— on ๐‘ โƒ— = ๐Ÿ/("|" ๐’ƒ โƒ—"|" ) (๐’‚ โƒ—. ๐’ƒ โƒ—) Now, (๐’‚ โƒ—. ๐’ƒ โƒ—) = (3๐‘– ฬ‚ โˆ’ ๐‘— ฬ‚ โˆ’ 2๐‘˜ ฬ‚ ) . (๐‘– ฬ‚ + 2๐‘— ฬ‚ โˆ’ 3๐‘˜ ฬ‚) = (3 ร— 1) + (โ€“1 ร— 2) + (โˆ’2 ร— โˆ’3) = 7 Magnitude of ๐‘ โƒ— = โˆš(12+22+(โˆ’3) 2) |๐’ƒ โƒ— | = โˆš(1+4+9) = โˆš๐Ÿ๐Ÿ’ Thus, Projection of ๐’‚ โƒ— on ๐’ƒ โƒ— = 1/("|" ๐‘ โƒ—"|" ) (๐‘Ž โƒ—. ๐‘ โƒ—) = ๐Ÿ•/โˆš๐Ÿ๐Ÿ’ So, the correct answer is (a)

  1. Class 12
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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo