Ex 12.2, 2 (ii) - Chapter 12 Class 8 Factorisation
Last updated at December 16, 2024 by Teachoo
Ex 12.2
Ex 12.2, 1 (i)
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Chapter 12 Class 8 Factorisation
Serial order wise
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Transcript
Ex 12.2, 2 Factorise. (ii) 63𝑎^2 – 112𝑏^263𝑎^2 – 112𝑏^2 = (7 × 9)𝑎^2− (7 × 16)𝑏^2 Taking 7 common, = 7 (9𝑎^2−16b^2) = 7 ((𝟑𝒂^𝟐 )−(𝟒𝒃)^𝟐 ) Using 𝒙^𝟐−𝒚^𝟐=(𝑥+𝑦)(𝑥−𝑦) Here 𝑥=3𝑎 and 𝑦=4𝑏 = 7 (𝟑𝒂+𝟒𝒃) (𝟑𝒂−𝟒𝒃)
