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Ex 14.2, 1 (vi) - Factorise 121b^2 - 88bc + 16c^2 - Ex 14.2


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Ex 14.2, 1 Factorise the following expressions. (vi) 121𝑏^2 – 88bc + 16𝑐^2 121𝑏^2 – 88bc + 16𝑐^2 = (11𝑏)^2−88𝑏𝑐+(4𝑐)^2 = (11𝑏)^2−2×11𝑏×4𝑐+(4𝑐)^2 = (11𝑏)^2+(4𝑐)^2−2×11𝑏×4𝑐 Using (𝑥−𝑦^2 )=𝑥^2+𝑦^2−2𝑥𝑦 Here, 𝑥 = 11b and y = 4c = 〖(𝟏𝟏𝒃−𝟒𝒄)〗^𝟐

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.