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Ex 14.2, 2 (ii) - Factorise 63^a2 - 112b^2 - Ex 14.2


Transcript

Ex 14.2, 2 Factorise. (ii) 63𝑎^2 – 112𝑏^2 63𝑎^2 – 112𝑏^2 = (7 × 9)𝑎^2− (7 × 16)𝑏^2 Taking 7 common, = 7 (9𝑎^2−16b^2) = 7 ((3𝑎^2 )−(4𝑏)^2 ) Using 𝑥^2−𝑦^2=(𝑥+𝑦)(𝑥−𝑦) Here 𝑥=3𝑎 and 𝑦=4𝑏 = 7 (𝟑𝒂+𝟒𝒃) (𝟑𝒂−𝟒𝒃)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.