Ex 14.2, 2 (iv) - Chapter 14 Class 8 Factorisation
Last updated at Dec. 26, 2018 by Teachoo
Transcript
Ex 14.2, 2 Factorise. (iv) 16๐ฅ^5 โ 144๐ฅ^3 16๐ฅ^5 โ 144๐ฅ^3 = ใ16๐ฅใ^2 ๐ฅ^3โ144๐ฅ^3 Taking ๐ฅ^3 common, = ๐ฅ^3 (16๐ฅ^2โ144) = ๐ฅ^3 ((4๐ฅ)^2โ(12)^2 ) Using ๐^2โ ๐^2 = (a + b) (a โ b) Here a = 4x and b = 12 = ๐ฅ^3 (4๐ฅ+12) (4๐ฅโ12) Both have 4 as common factor = ๐ฅ^3 ร 4 (๐ฅ + 3) ร 4 (๐ฅ โ 3) = ๐ฅ^3 ร 4 ร 4 (๐ฅ + 3) (๐ฅ โ 3) = 16๐^๐ (๐ + 3) (๐ โ 3)
Ex 14.2
Ex 14.2, 1 (i)
Ex 14.2, 1 (ii)
Ex 14.2, 1 (iii)
Ex 14.2, 1 (iv)
Ex 14.2, 1 (v)
Ex 14.2, 1 (vi) Important
Ex 14.2, 1 (vii)
Ex 14.2, 1 (viii) Important
Ex 14.2, 2 (i)
Ex 14.2, 2 (ii)
Ex 14.2, 2 (iii)
Ex 14.2, 2 (iv) You are here
Ex 14.2, 2 (v)
Ex 14.2, 2 (vi)
Ex 14.2, 2 (vii)
Ex 14.2, 2 (viii) Important
Ex 14.2, 3 (i)
Ex 14.2, 3 (ii)
Ex 14.2, 3 (iii) Important
Ex 14.2, 3 (iv) Important
Ex 14.2, 3 (v)
Ex 14.2, 3 (vi)
Ex 14.2, 3 (vii) Important
Ex 14.2, 3 (viii) Important
Ex 14.2, 3 (ix)
Ex 14.2, 4 (i)
Ex 14.2, 4 (ii)
Ex 14.2, 4 (iii)
Ex 14.2, 4 (iv) Important
Ex 14.2, 4 (v) Important
Ex 14.2, 5 (i)
Ex 14.2, 5 (ii) Important
Ex 14.2, 5 (iii)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.