Ex 14.2, 4 (iv) - Chapter 14 Class 8 Factorisation
Last updated at Dec. 26, 2018 by Teachoo
Ex 14.2
Ex 14.2, 1 (i)
Ex 14.2, 1 (ii)
Ex 14.2, 1 (iii) Important
Ex 14.2, 1 (iv) Important
Ex 14.2, 1 (v)
Ex 14.2, 1 (vi)
Ex 14.2, 1 (vii) Important
Ex 14.2, 1 (viii)
Ex 14.2, 2 (i)
Ex 14.2, 2 (ii) Important
Ex 14.2, 2 (iii)
Ex 14.2, 2 (iv) Important
Ex 14.2, 2 (v)
Ex 14.2, 2 (vi)
Ex 14.2, 2 (vii) Important
Ex 14.2, 2 (viii) Important
Ex 14.2, 3 (i)
Ex 14.2, 3 (ii) Important
Ex 14.2, 3 (iii)
Ex 14.2, 3 (iv) Important
Ex 14.2, 3 (v) Important
Ex 14.2, 3 (vi)
Ex 14.2, 3 (vii)
Ex 14.2, 3 (viii) Important
Ex 14.2, 3 (ix)
Ex 14.2, 4 (i)
Ex 14.2, 4 (ii) Important
Ex 14.2, 4 (iii)
Ex 14.2, 4 (iv) Important You are here
Ex 14.2, 4 (v) Important
Ex 14.2, 5 (i)
Ex 14.2, 5 (ii) Important
Ex 14.2, 5 (iii)
Transcript
Ex 14.2, 4 Factorise. (iv) 𝑥^4 – 〖"(x – z)" 〗^4 𝑥^4 – 〖"(x – z)" 〗^4 = 〖(𝑥^2)〗^2 − [(𝑥 − z)^2 ]^2 Using 𝑎^2 − 𝑏^2 = (a + b) (a − b) Here 𝑎=𝑥^2 and b = (𝑥 − z)^2 = [𝑥^2+(𝑥 − z)^2 ] [𝑥^2 −(𝑥 − z)^2] Asking Using 𝑎^2 − 𝑏^2 = (a + b) (a − b) Here 𝑎=𝑥 and b = (𝑥 − z) Asking Using 𝑎^2 − 𝑏^2 = (a + b) (a − b) Here 𝑎=𝑥 and b = (𝑥 − z) = [𝑥^2+(𝑥 − z)^2 ] [2𝑥− z] [𝑧] Using 𝑎^2 − 𝑏^2 = 𝑎^2+𝑏^2 − 2ab Here 𝑎=𝑥 and b = 𝑧 Using 𝑎^2 − 𝑏^2 = 𝑎^2+𝑏^2 − 2ab Here 𝑎=𝑥 and b = 𝑧
