Ex 14.2, 2 (viii) - Chapter 14 Class 8 Factorisation
Last updated at Dec. 26, 2018 by Teachoo
Transcript
Ex 14.2, 2 Factorise. (viii) 25๐^2 โ 4๐^2 + 28bc โ 49๐^2 25๐^2 โ 4๐^2 + 28bc โ 49๐^2 Taking โ common = 25๐^2 โ (4๐^2 โ 28bc +49๐^2) = 25๐^2 โ (4๐^2 + 49๐^2 + 28bc) = 25๐^2 โ ((2b)2 + (7c)2 โ 2 ร 2b ร 7c) Using (x โ y)2 = x2 + y2 โ 2xy Here x = 2b and y = 7c = 25๐^2 โ "(2b โ " ใ"7c)" ใ^2 = (5a)2 โ "(2b โ " ใ"7c)" ใ^2 Using ๐ฅ^2 โ ๐ฆ^2 = (๐ฅ + y) (๐ฅ โ y) Here x = 5a and y = 2b โ 7c Using ๐ฅ^2 โ ๐ฆ^2 = (๐ฅ + y) (๐ฅ โ y) Here x = 5a and y = 2b โ 7c
Ex 14.2
Ex 14.2, 1 (i)
Ex 14.2, 1 (ii)
Ex 14.2, 1 (iii)
Ex 14.2, 1 (iv)
Ex 14.2, 1 (v)
Ex 14.2, 1 (vi) Important
Ex 14.2, 1 (vii)
Ex 14.2, 1 (viii) Important
Ex 14.2, 2 (i)
Ex 14.2, 2 (ii)
Ex 14.2, 2 (iii)
Ex 14.2, 2 (iv)
Ex 14.2, 2 (v)
Ex 14.2, 2 (vi)
Ex 14.2, 2 (vii)
Ex 14.2, 2 (viii) Important You are here
Ex 14.2, 3 (i)
Ex 14.2, 3 (ii)
Ex 14.2, 3 (iii) Important
Ex 14.2, 3 (iv) Important
Ex 14.2, 3 (v)
Ex 14.2, 3 (vi)
Ex 14.2, 3 (vii) Important
Ex 14.2, 3 (viii) Important
Ex 14.2, 3 (ix)
Ex 14.2, 4 (i)
Ex 14.2, 4 (ii)
Ex 14.2, 4 (iii)
Ex 14.2, 4 (iv) Important
Ex 14.2, 4 (v) Important
Ex 14.2, 5 (i)
Ex 14.2, 5 (ii) Important
Ex 14.2, 5 (iii)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.