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Ex 14.2, 5 (ii) - Chapter 14 Class 8 Factorisation
Last updated at Dec. 26, 2018 by Teachoo
Transcript
Ex 14.2, 5 Factorise the following expressions. (ii) ๐^2 โ 10q + 21 ๐^2 โ 10q + 21 By middle term splitting = ๐^2โ3๐โ7๐+21 = (๐^2โ3๐)โ(7๐โ21) = q (q โ 3) โ 7(q โ 3) Taking (q โ 3) common, = (q โ 3) (q โ 7) Splitting the middle term We need to find two numbers whose Sum = โ10 Product = 21 So, we write โ10q = โ3q โ 7q
Ex 14.2
Ex 14.2, 1 (i)
Ex 14.2, 1 (ii)
Ex 14.2, 1 (iii)
Ex 14.2, 1 (iv)
Ex 14.2, 1 (v)
Ex 14.2, 1 (vi) Important
Ex 14.2, 1 (vii)
Ex 14.2, 1 (viii) Important
Ex 14.2, 2 (i)
Ex 14.2, 2 (ii)
Ex 14.2, 2 (iii)
Ex 14.2, 2 (iv)
Ex 14.2, 2 (v)
Ex 14.2, 2 (vi)
Ex 14.2, 2 (vii)
Ex 14.2, 2 (viii) Important
Ex 14.2, 3 (i)
Ex 14.2, 3 (ii)
Ex 14.2, 3 (iii) Important
Ex 14.2, 3 (iv) Important
Ex 14.2, 3 (v)
Ex 14.2, 3 (vi)
Ex 14.2, 3 (vii) Important
Ex 14.2, 3 (viii) Important
Ex 14.2, 3 (ix)
Ex 14.2, 4 (i)
Ex 14.2, 4 (ii)
Ex 14.2, 4 (iii)
Ex 14.2, 4 (iv) Important
Ex 14.2, 4 (v) Important
Ex 14.2, 5 (i)
Ex 14.2, 5 (ii) Important You are here
Ex 14.2, 5 (iii)
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.