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Ex 12.2, 5 (ii) - Chapter 12 Class 8 Factorisation
Last updated at Aug. 8, 2023 by Teachoo
Ex 12.2
Ex 12.2, 1 (i)
Ex 12.2, 1 (ii)
Ex 12.2, 1 (iii) Important
Ex 12.2, 1 (iv) Important
Ex 12.2, 1 (v)
Ex 12.2, 1 (vi)
Ex 12.2, 1 (vii) Important
Ex 12.2, 1 (viii)
Ex 12.2, 2 (i)
Ex 12.2, 2 (ii) Important
Ex 12.2, 2 (iii)
Ex 12.2, 2 (iv) Important
Ex 12.2, 2 (v)
Ex 12.2, 2 (vi)
Ex 12.2, 2 (vii) Important
Ex 12.2, 2 (viii) Important
Ex 12.2, 3 (i)
Ex 12.2, 3 (ii) Important
Ex 12.2, 3 (iii)
Ex 12.2, 3 (iv) Important
Ex 12.2, 3 (v) Important
Ex 12.2, 3 (vi)
Ex 12.2, 3 (vii)
Ex 12.2, 3 (viii) Important
Ex 12.2, 3 (ix)
Ex 12.2, 4 (i)
Ex 12.2, 4 (ii) Important
Ex 12.2, 4 (iii)
Ex 12.2, 4 (iv) Important
Ex 12.2, 4 (v) Important
Ex 12.2, 5 (i)
Ex 12.2, 5 (ii) Important You are here
Ex 12.2, 5 (iii)
Chapter 12 Class 8 Factorisation
Serial order wise
Transcript
Ex 12.2, 5 Factorise the following expressions. (ii) 𝑞^2 – 10q + 21𝑞^2 – 10q + 21 By middle term splitting = 𝑞^2−𝟑𝒒−𝟕𝒒+21 = (𝑞^2−3𝑞)−(7𝑞−21) = q (q − 3) − 7(q − 3) Taking (q − 3) common, = (q − 3) (q − 7) Splitting the middle term We need to find two numbers whose Sum = −10 Product = 21 So, we write −10q = −3q − 7q
