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Ex 12.2, 5 (iii) - Chapter 12 Class 8 Factorisation
Last updated at Aug. 8, 2023 by Teachoo
Ex 12.2
Ex 12.2, 1 (i)
Ex 12.2, 1 (ii)
Ex 12.2, 1 (iii) Important
Ex 12.2, 1 (iv) Important
Ex 12.2, 1 (v)
Ex 12.2, 1 (vi)
Ex 12.2, 1 (vii) Important
Ex 12.2, 1 (viii)
Ex 12.2, 2 (i)
Ex 12.2, 2 (ii) Important
Ex 12.2, 2 (iii)
Ex 12.2, 2 (iv) Important
Ex 12.2, 2 (v)
Ex 12.2, 2 (vi)
Ex 12.2, 2 (vii) Important
Ex 12.2, 2 (viii) Important
Ex 12.2, 3 (i)
Ex 12.2, 3 (ii) Important
Ex 12.2, 3 (iii)
Ex 12.2, 3 (iv) Important
Ex 12.2, 3 (v) Important
Ex 12.2, 3 (vi)
Ex 12.2, 3 (vii)
Ex 12.2, 3 (viii) Important
Ex 12.2, 3 (ix)
Ex 12.2, 4 (i)
Ex 12.2, 4 (ii) Important
Ex 12.2, 4 (iii)
Ex 12.2, 4 (iv) Important
Ex 12.2, 4 (v) Important
Ex 12.2, 5 (i)
Ex 12.2, 5 (ii) Important
Ex 12.2, 5 (iii) You are here
Chapter 12 Class 8 Factorisation
Serial order wise
Transcript
Ex 12.2, 5 Factorise the following expressions. (iii) 𝑝^2 + 6p – 16𝑝^2 + 6p – 16 By middle term splitting = 𝑝^2 −𝟐𝒑+𝟖𝒑 − 16 = (𝑝^2−2𝑝)+(8𝑝 − 1"6") = p (p − 2) + 8 (p − 2) Taking (p − 2) common = (p − 2) (p + 8) Splitting the middle term We need to find two numbers whose Sum = 6 Product = −16 So, we write 6p = −2p + 8p
