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Ex 14.2, 3 (iii) - Chapter 14 Class 8 Factorisation
Last updated at Dec. 26, 2018 by Teachoo
Transcript
Ex 14.2, 3 (Method 1) Factorise the expressions. (iii) 2๐ฅ^3 + 2ใ๐ฅ๐ฆใ^2 + 2x๐ง^2 2๐ฅ^3 = 2 ร ๐ฅ^3 = 2 ร ๐ฅ^3 2ใ๐ฅ๐ฆใ^2= 2 ร ๐ฅ ร ๐ฆ^2 = 2 ร ๐ฅ ร ๐ฆ ร ๐ฆ 2x๐ง^2 = 2 ร ๐ฅ ร ๐ง^2 = 2 ร ๐ฅ ร ๐ง ร ๐ง 2๐ฅ^3 + 2ใ๐ฅ๐ฆใ^2 + 2x๐ง^2 = (2 ร ๐ฅ ร ๐ฅ ร ๐ฅ) + (2 ร ๐ฅ ร ๐ฆ ร ๐ฆ) + (2 ร ๐ฅ ร ๐ง ร ๐ง) Taking 2 ร ๐ฅ Common, = 2 ร ๐ฅ ((๐ฅ ร ๐ฅ) + (y ร y) + (z ร z)) = 2๐ (๐^๐ + ๐^๐ + ๐^๐) Ex 14.2, 3 (Method 2) Factorise the expressions. (iii) 2๐ฅ^3 + 2ใ๐ฅ๐ฆใ^2 + 2x๐ง^2 2๐ฅ^3 + 2ใ๐ฅ๐ฆใ^2 + 2x๐ง^2 = (2 ร ๐ฅ^3) + (2 ร ใ๐ฅ๐ฆใ^2) + (2 ร ๐ฅ๐ง^2) Taking 2 common = 2 (๐ฅ^3 + ใ๐ฅ๐ฆใ^2 + ๐ฅ๐ง^2) = 2 ((๐ฅ ร ๐ฅ^2) + (๐ฅ ร ๐ฆ^2) + (๐ฅ ร ๐ง^2)) Taking ๐ฅ common, = 2๐ (๐^๐ + ๐^๐ + ๐^๐) 2๐ฅ^3 + 2ใ๐ฅ๐ฆใ^2 + 2x๐ง^2 = (2 ร ๐ฅ^3) + (2 ร ใ๐ฅ๐ฆใ^2) + (2 ร ๐ฅ๐ง^2) Taking 2 common = 2 (๐ฅ^3 + ใ๐ฅ๐ฆใ^2 + ๐ฅ๐ง^2) = 2 ((๐ฅ ร ๐ฅ^2) + (๐ฅ ร ๐ฆ^2) + (๐ฅ ร ๐ง^2)) Taking ๐ฅ common, = 2๐ (๐^๐ + ๐^๐ + ๐^๐)
Ex 14.2
Ex 14.2, 1 (i)
Ex 14.2, 1 (ii)
Ex 14.2, 1 (iii)
Ex 14.2, 1 (iv)
Ex 14.2, 1 (v)
Ex 14.2, 1 (vi) Important
Ex 14.2, 1 (vii)
Ex 14.2, 1 (viii) Important
Ex 14.2, 2 (i)
Ex 14.2, 2 (ii)
Ex 14.2, 2 (iii)
Ex 14.2, 2 (iv)
Ex 14.2, 2 (v)
Ex 14.2, 2 (vi)
Ex 14.2, 2 (vii)
Ex 14.2, 2 (viii) Important
Ex 14.2, 3 (i)
Ex 14.2, 3 (ii)
Ex 14.2, 3 (iii) Important You are here
Ex 14.2, 3 (iv) Important
Ex 14.2, 3 (v)
Ex 14.2, 3 (vi)
Ex 14.2, 3 (vii) Important
Ex 14.2, 3 (viii) Important
Ex 14.2, 3 (ix)
Ex 14.2, 4 (i)
Ex 14.2, 4 (ii)
Ex 14.2, 4 (iii)
Ex 14.2, 4 (iv) Important
Ex 14.2, 4 (v) Important
Ex 14.2, 5 (i)
Ex 14.2, 5 (ii) Important
Ex 14.2, 5 (iii)
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.