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Ex 12.2

Ex 12.2, 1 (i)

Ex 12.2, 1 (ii)

Ex 12.2, 1 (iii) Important

Ex 12.2, 1 (iv) Important

Ex 12.2, 1 (v)

Ex 12.2, 1 (vi)

Ex 12.2, 1 (vii) Important

Ex 12.2, 1 (viii)

Ex 12.2, 2 (i)

Ex 12.2, 2 (ii) Important

Ex 12.2, 2 (iii)

Ex 12.2, 2 (iv) Important

Ex 12.2, 2 (v)

Ex 12.2, 2 (vi)

Ex 12.2, 2 (vii) Important

Ex 12.2, 2 (viii) Important

Ex 12.2, 3 (i)

Ex 12.2, 3 (ii) Important

Ex 12.2, 3 (iii) You are here

Ex 12.2, 3 (iv) Important

Ex 12.2, 3 (v) Important

Ex 12.2, 3 (vi)

Ex 12.2, 3 (vii)

Ex 12.2, 3 (viii) Important

Ex 12.2, 3 (ix)

Ex 12.2, 4 (i)

Ex 12.2, 4 (ii) Important

Ex 12.2, 4 (iii)

Ex 12.2, 4 (iv) Important

Ex 12.2, 4 (v) Important

Ex 12.2, 5 (i)

Ex 12.2, 5 (ii) Important

Ex 12.2, 5 (iii)

Chapter 12 Class 8 Factorisation

Serial order wise

Last updated at Aug. 8, 2023 by Teachoo

Ex 12.2, 3 (Method 1) Factorise the expressions. (iii) 2𝑥^3 + 2〖𝑥𝑦〗^2 + 2x𝑧^22𝑥^3 + 2〖𝑥𝑦〗^2 + 2x𝑧^2 = (2 × 𝑥^3) + (2 × 〖𝑥𝑦〗^2) + (2 × 𝑥𝑧^2) Taking 2 common = 2 (𝑥^3 + 〖𝑥𝑦〗^2 + 𝑥𝑧^2) = 2 ((𝑥 × 𝑥^2) + (𝑥 × 𝑦^2) + (𝑥 × 𝑧^2)) Taking 𝑥 common, = 2𝒙 (𝒙^𝟐 + 𝒚^𝟐 + 𝒛^𝟐) Ex 12.2, 3 (Method 2) Factorise the expressions. (iii) 2𝑥^3 + 2〖𝑥𝑦〗^2 + 2x𝑧^2 2𝑥^3 2〖𝑥𝑦〗^2 2x𝑧^2 So, 2 and 𝒙 are the common factors. 2𝑥^3 + 2〖𝑥𝑦〗^2 + 2x𝑧^2 = (2 × 𝑥 × 𝑥 × 𝑥) + (2 × 𝑥 × 𝑦 × 𝑦) + (2 × 𝑥 × 𝑧 × 𝑧) Taking 2 × 𝑥 Common, = 2 × 𝑥 ((𝑥 × 𝑥) + (y × y) + (z × z)) = 2𝒙 (𝒙^𝟐 + 𝒚^𝟐 + 𝒛^𝟐) = 2 × 𝑥 × 𝑥 × 𝑥 = 2 × 𝑥 × 𝑦 × 𝑦 = 2 × 𝑥 × 𝑧 × 𝑧