Question 12 (OR 2 nd question)

If P(A) = 0.6, P(B) = 0.5 and P(A|B) = 0.3, then find P(A ∪ B).

If P(A) = 0.6, P(B) = 0.5 and P(A|B) = 0.3, then find P(A U B).

Question 12 (Or 2nd) - CBSE Class 12 Sample Paper for 2019 Boards - Part 2

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Question 12 (OR 2nd question) If P(A) = 0.6, P(B) = 0.5 and P(A|B) = 0.3, then find P(A ∪ B). Given, P(A) = 0.6 P(B) = 0.5 & P(A|B) = 0.3 Now, P(A|B) = (𝑃(𝐴" ∩ " 𝐵))/(𝑃(𝐵)) 0.3 = (𝑃(𝐴" ∩ " 𝐵))/0.5 0.3 × 0.5 = P (A ∩ B) 3/10 × 5/10 = P (A ∩ B) 15/100 = P (A ∩ B) 0.15 = P (A ∩ B) P (A ∩ B) = 0.15 Now, P(A ∪ B) = P(A) + P(B) – P(A ∩ B) = 0.6 + 0.5 – 0.15 = 1.1 – 0.15 = 0.95

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.