Question 12 (OR 2 nd question)

If P(A) = 0.6, P(B) = 0.5 and P(A|B) = 0.3, then find P(A ∪ B).

If P(A) = 0.6, P(B) = 0.5 and P(A|B) = 0.3, then find P(A U B).

Question 12 (Or 2nd) - CBSE Class 12 Sample Paper for 2019 Boards - Part 2


Transcript

Question 12 (OR 2nd question) If P(A) = 0.6, P(B) = 0.5 and P(A|B) = 0.3, then find P(A ∪ B). Given, P(A) = 0.6 P(B) = 0.5 & P(A|B) = 0.3 Now, P(A|B) = (𝑃(𝐴" ∩ " 𝐵))/(𝑃(𝐵)) 0.3 = (𝑃(𝐴" ∩ " 𝐵))/0.5 0.3 × 0.5 = P (A ∩ B) 3/10 × 5/10 = P (A ∩ B) 15/100 = P (A ∩ B) 0.15 = P (A ∩ B) P (A ∩ B) = 0.15 Now, P(A ∪ B) = P(A) + P(B) – P(A ∩ B) = 0.6 + 0.5 – 0.15 = 1.1 – 0.15 = 0.95

Go Ad-free
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.