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Question 10 (OR 1
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st
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question)
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Find the area of the parallelogram whose diagonals are represented by the vectors a = 2i – 3j + 4k and b = 2i – j + 2k

We use the Area of Parallelogram formula with Diagonals

Last updated at Nov. 1, 2018 by Teachoo

**
Question 10 (OR 1
**
**
st
**
**
question)
**

Find the area of the parallelogram whose diagonals are represented by the vectors a = 2i – 3j + 4k and b = 2i – j + 2k

We use the Area of Parallelogram formula with Diagonals

Transcript

Question 10 (OR 1st question) Find the area of the parallelogram whose diagonals are represented by the vectors ๐ โ = 2๐ ฬ โ 3๐ ฬ + 4๐ ฬ and ๐ โ = 2๐ ฬ โ ๐ ฬ + 2๐ ฬ Area of parallelograms with diagonal Area = 1/2 |(๐_1 ) โร(๐_2 ) โ | Given Diagonals of a parallelogram as ๐ โ = 2๐ ฬ โ 3๐ ฬ + 4๐ ฬ and ๐ โ = 2๐ ฬ โ ๐ ฬ + 2๐ ฬ Area of the parallelogram = 1/2 |๐ โร๐ โ | Finding ๐ โ ร ๐ โ ๐ โ ร ๐ โ = |โ 8(๐ ฬ&๐ ฬ&๐ ฬ@2&โ3&4@2&โ1&2)| = ๐ ฬ ((โ3) ร 2 โ (-1) ร 4) โ ๐ ฬ (2 ร 2 โ 2 ร 4) + ๐ ฬ (2 ร (-1) โ 2 ร (-3)) = ๐ ฬ (-6 + 4) โ ๐ ฬ (4 โ 8) + ๐ ฬ (โ2 + 6) = ๐ ฬ (โ2) - ๐ ฬ (โ4) + ๐ ฬ (4) = โ2๐ ฬ + 4๐ ฬ + 4๐ ฬ So, Magnitude of ๐ โ ร ๐ โ = โ((โ2)2+(4)2+(4)2) |๐ โ" ร " ๐ โ | = โ(4+16+16) |๐ โ" ร " ๐ โ |= โ36 |๐ โ" ร " ๐ โ |= 6 Thus, Area of the parallelogram = 1/2 |๐ โร๐ โ | = 1/2 ร 6 = 3 square units

CBSE Class 12 Sample Paper for 2019 Boards

Paper Summary

Question 1

Question 2

Question 3

Question 4 (Or 1st)

Question 4 (Or 2nd)

Question 5

Question 6

Question 7

Question 8 (Or 1st)

Question 8 (Or 2nd)

Question 9

Question 10 (Or 1st) You are here

Question 10 (Or 2nd)

Question 11

Question 12 (Or 1st)

Question 12 (Or 2nd)

Question 13 (Or 1st)

Question 13 (Or 2nd)

Question 14

Question 15

Question 16 (Or 1st)

Question 16 (Or 2nd)

Question 17

Question 18

Question 19

Question 20

Question 21 (Or 1st)

Question 21 (Or 2nd)

Question 22

Question 23

Question 24 (Or 1st)

Question 24 (Or 2nd)

Question 25

Question 26 (Or 1st)

Question 26 (Or 2nd)

Question 27 (Or 1st)

Question 27 (Or 2nd)

Question 28

Question 29

Class 12

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.