Question 4 (OR 2 nd question)

Find the direction cosines of the line:

  (x - 1)/2 = –y = (z + 1)/2

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Question 4 (OR 2nd question) Find the direction cosines of the line: (๐‘ฅ โˆ’ 1)/2 = โ€“y = (๐‘ง + 1)/2 Given line (๐‘ฅ โˆ’ 1)/2 = โ€“y = (๐‘ง + 1)/2 (๐‘ฅ โˆ’ 1)/2 = (โˆ’๐‘ฆ)/1 = (๐‘ง + 1)/2 (๐‘ฅ โˆ’ 1)/2 = ๐‘ฆ/(โˆ’1) = (๐‘ง + 1)/2 So, direction ratios are 2, โ€“1, 2 โˆด a = 2, b = โ€“1, c = 2 Direction cosines = 2/โˆš(2^2 + (โˆ’1)^2 + 2^2 ) ,(โˆ’1)/โˆš(2^2 + (โˆ’1)^2 + 2^2 ) ,2/โˆš(2^2 + (โˆ’1)^2 + 2^2 ) = 2/โˆš(4 + 1 + 4) ,(โˆ’1)/โˆš(4 + 1 + 4) ,2/โˆš(4 + 1 + 4) = 2/โˆš9 ,(โˆ’1)/โˆš9 ,2/โˆš9 = ๐Ÿ/๐Ÿ‘ ,(โˆ’๐Ÿ)/๐Ÿ‘ ,๐Ÿ/๐Ÿ‘

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.