Question 2

Differentiate sin 2 โก (x 2 )  w.r.t x 2

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Question 2 Differentiate sin^2โกใ€–(๐‘ฅ^2)ใ€— w.r.t ๐‘ฅ^2 We need to find ๐‘‘(sin^2โก(๐‘ฅ^2 ) )/(๐‘‘๐‘ฅ^2 ) Let x2 = t So, we need to find ๐‘‘(sin^2โก๐‘ก )/๐‘‘๐‘ก = 2 sin t ร— (sin t)โ€™ = 2 sin t ร— cos t Putting t = x2 = 2 sin (x2) cos (x2)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.