Question 2
Differentiate sin ^{ 2 } โก (x ^{ 2 } ) w.r.t x ^{ 2 }
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Last updated at Oct. 1, 2019 by Teachoo
Question 2
Differentiate sin ^{ 2 } โก (x ^{ 2 } ) w.r.t x ^{ 2 }
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Transcript
Question 2 Differentiate sin^2โกใ(๐ฅ^2)ใ w.r.t ๐ฅ^2 We need to find ๐(sin^2โก(๐ฅ^2 ) )/(๐๐ฅ^2 ) Let x2 = t So, we need to find ๐(sin^2โก๐ก )/๐๐ก = 2 sin t ร (sin t)โ = 2 sin t ร cos t Putting t = x2 = 2 sin (x2) cos (x2)
CBSE Class 12 Sample Paper for 2019 Boards
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CBSE Class 12 Sample Paper for 2019 Boards
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