Example 37 - Chapter 7 Class 12 Integrals (Term 2)
Last updated at May 29, 2018 by Teachoo
Last updated at May 29, 2018 by Teachoo
Transcript
Example 37 Evaluate cos 6 1+ sin 6 cos 6 1+ sin 6 Put = 1+ sin 6 2 = 1+ sin 6 Differentiate . . . 2 = 1+ sin 6 2 . =6 cos 6 2 6 cos 6 = Therefore, cos 6 1+ sin 6 = cos 6 . 2 6 cos 6 = 2 3 = 1 3 2 = 1 3 2 + 1 2 + 1 + = 1 3 3 3 + = 3 9 + Putting back = 1+ 6 = 1 + sin 6 3 9 + = 1 + sin 6 1 2 3 9 + = + +
Integration by substitution - Trignometric - Normal
Example 5 (i)
Ex 7.2, 22 Important
Misc 15
Example 37 You are here
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Ex 7.2, 26 Important
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Example 6 (i)
Ex 7.2, 29 Important
Ex 7.2, 21
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Ex 7.2, 39 (MCQ) Important
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Misc 7 Important
Integration by substitution - Trignometric - Normal
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