Ex 9.5, 12 - Chapter 9 Class 12 Differential Equations
Last updated at April 16, 2024 by Teachoo
Ex 9.5
Ex 9.5, 2
Ex 9.5, 3 Important
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Ex 9.5, 5 Important
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Ex 9.5, 7 Important
Ex 9.5, 8 Important
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Ex 9.5, 12 Important You are here
Ex 9.5, 13
Ex 9.5, 14 Important
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Ex 9.5, 16 Important
Ex 9.5, 17 Important
Ex 9.5, 18 (MCQ)
Ex 9.5, 19 (MCQ) Important
Last updated at April 16, 2024 by Teachoo
Ex 9.5, 12 For each of the differential equation find the general solution : (π₯+3π¦^2 ) ππ¦/ππ₯=π¦(π¦>0) Step 1 : Put In form ππ¦/ππ₯ + py = Q or ππ₯/ππ¦ + P1x = Q1 (π₯+3π¦^2 ) ππ¦/ππ₯=π¦ ππ¦/ππ₯ = π¦/(π₯+3π¦^2 ) This is not of the form ππ¦/ππ₯ + Py = Q β΄ We need to find π π/π π ππ₯/ππ¦ = (π₯ + 3π¦^2)/π¦ π π/π π = π/π + (ππ^π)/π Step 2 : Find P1 and Q1 Comparing with ππ¦/ππ₯ + P1x = Q1 where P1 = (βπ)/π & Q1 = 3y Step 3 : Finding Integrating factor IF = π^(β«1βπ_π π π) IF = π^(β«1β(β1)/π¦ ππ¦" " ) IF = eβlog y IF = π^logβ‘γπ¦^(β1) γ IF = yβ1 IF = π/π Step 4 : Solution of the equation Solution is x(IF) = β«1βγ(π1ΓπΌπΉ)ππ¦+πΆγ x(1/π¦)=β«1βγ3π¦Γ1/π¦ ππ¦+πΆγ π₯/π¦ = 3β«1βγππ¦+πΆγ π₯/π¦ = 3π¦+πΆ π = ππ^π+πͺy