Ex 9.5, 11 - Chapter 9 Class 12 Differential Equations
Last updated at April 16, 2024 by Teachoo
Ex 9.5
Ex 9.5, 2
Ex 9.5, 3 Important
Ex 9.5, 4
Ex 9.5, 5 Important
Ex 9.5, 6
Ex 9.5, 7 Important
Ex 9.5, 8 Important
Ex 9.5, 9
Ex 9.5, 10
Ex 9.5, 11 You are here
Ex 9.5, 12 Important
Ex 9.5, 13
Ex 9.5, 14 Important
Ex 9.5, 15
Ex 9.5, 16 Important
Ex 9.5, 17 Important
Ex 9.5, 18 (MCQ)
Ex 9.5, 19 (MCQ) Important
Last updated at April 16, 2024 by Teachoo
Ex 9.5, 11 For each of the differential equation find the general solution : π¦ ππ₯+(π₯βπ¦^2 )ππ¦=0 Step 1 : Put in form ππ¦/ππ₯ + Py = Q or ππ₯/ππ¦ + P1 x = Q1, y dx + (x β y2) dy = 0 y dx = β (x β y2)dy ππ¦/ππ₯ = (βπ¦)/(π₯βπ¦^2 ) This is not of the form ππ¦/ππ₯ + Py = Q β΄ We find π π/π π ππ₯/ππ¦ = (π¦^2 β π₯)/π¦ ππ₯/ππ¦ = y β π₯/π¦ π π/π π + π/π = y Step 2 : Find P1 and Q1 Comparing (1) with ππ₯/ππ¦ + P1 x = Q1 Where P1 = π/π & Q1 = y Step 3 : Find Integrating factor, IF = π^β«1βγππ π πγ = π^β«1βππ¦/π¦ = π^logβ‘π¦ = y Step 4 : Solution of the equation Solution is x (IF) = β«1βγ(π1ΓπΌπΉ)ππ¦+πγ xy = β«1βγπΓπ π π+πγ xy = β«1βγπ¦^2 ππ¦+πγ xy = π¦^3/3+πΆ x = π¦^3/3π¦+πΆ/π¦ x = π^π/π+πͺ/π