
Ex 9.5
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Ex 9.5, 3 For each of the differential equation given in Exercises 1 to 12, find the general solution : ππ¦/ππ₯+π¦/π₯=π₯^2 ππ¦/ππ₯+π¦/π₯=π₯^2 Differential equation is of the form ππ¦/ππ₯+ππ¦=π where P = π/π and Q = x2 Finding integrating factor, I.F = e^β«1βγπ ππ₯γ IF = e^β«1βγ1/π₯ ππ₯γ IF = e^logβ‘π₯ IF = x Solution is y (IF) = β«1βγ(πΓπΌπΉ)ππ₯+πγ yx = β«1βγπ^πΓπΓπ π+πγ yx = β«1βγπ₯^3 ππ₯+πγ yx = π₯^4/4+π xy = π^π/π+π