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Ex 9.6, 4 - Find general solution: dy/dx + (sec x) y = tan x - Solving Linear differential equations - Equation given

Ex 9.6, 4 - Chapter 9 Class 12 Differential Equations - Part 2

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Ex 9.6, 4 For each of the differential equation given in Exercises 1 to 12, find the general solution : + sec = 0 < 2 Differential equation is of the form + Py = Q where P = sec x and Q = tan x Finding integrating factor, IF = IF = e sec IF = e sec + tan I.F = sec x + tan x Solution is y (IF) = . + y (sec x + tan x) = tan ( sec + tan ) + y (sec x + tan x) = tan sec + tan 2 + y (sec x + tan x) = sec x + ( sec 2 1) dx + c y (sec x + tan x) = sec x + x + c

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.