# Ex 9.5, 4 - Chapter 9 Class 12 Differential Equations

Last updated at April 16, 2024 by Teachoo

Ex 9.5

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Ex 9.5, 4 You are here

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Ex 9.5, 18 (MCQ)

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Last updated at April 16, 2024 by Teachoo

Ex 9.5, 4 For each of the differential equation given in Exercises 1 to 12, find the general solution : ππ¦/ππ₯+(secβ‘π₯ )π¦=π‘πππ₯(0β€π₯<π/2) Differential equation is of the form ππ¦/ππ₯ + Py = Q where P = sec x and Q = tan x Finding integrating factor, IF = π^β«1βγπ ππ₯γ IF = e^β«1βsecβ‘γπ₯ ππ₯γ IF = γe^πππγ^|secβ‘γπ₯ + tanβ‘π₯ γ | I.F = sec x + tan x Solution is y (IF) = β«1β(πΓπΌ.πΉ) ππ₯+π y (sec x + tan x) = β«1βγπππ§β‘π (πππβ‘π+πππ§β‘γπ)γ γ+π y (sec x + tan x) = β«1βγtanβ‘π₯ secβ‘π₯ γ ππ₯+β«1βγtan^2β‘π₯ ππ₯+πΆγ y (sec x + tan x) = sec x + β«1βγ(sec^2β‘π₯β1)γ dx + c y (sec x + tan x) = sec x + πππ§β‘π β x + c