Finding rate of change
Ex 6.1, 1 Deleted for CBSE Board 2022 Exams
Ex 6.1,17 (MCQ) Deleted for CBSE Board 2022 Exams
Example 5 Deleted for CBSE Board 2022 Exams
Ex 6.1,15 Important Deleted for CBSE Board 2022 Exams
Example 6 Deleted for CBSE Board 2022 Exams
Ex 6.1,16 Deleted for CBSE Board 2022 Exams
Ex 6.1, 18 (MCQ) Important Deleted for CBSE Board 2022 Exams
Example 2 Deleted for CBSE Board 2022 Exams
Ex 6.1,2 Deleted for CBSE Board 2022 Exams
Example 49 Deleted for CBSE Board 2022 Exams
Example 3 Deleted for CBSE Board 2022 Exams
Ex 6.1,5 Important Deleted for CBSE Board 2022 Exams
Ex 6.1,3 Deleted for CBSE Board 2022 Exams
Ex 6.1,6 Deleted for CBSE Board 2022 Exams
Ex 6.1,12 Deleted for CBSE Board 2022 Exams
Ex 6.1,13 Important Deleted for CBSE Board 2022 Exams
Misc. 19 (MCQ) Deleted for CBSE Board 2022 Exams You are here
Ex 6.1,14 Deleted for CBSE Board 2022 Exams
Example 43 Important Deleted for CBSE Board 2022 Exams
Ex 6.1,4 Important Deleted for CBSE Board 2022 Exams
Example 42 Important Deleted for CBSE Board 2022 Exams
Example 4 Important Deleted for CBSE Board 2022 Exams
Ex 6.1,7 Deleted for CBSE Board 2022 Exams
Ex 6.1,8 Deleted for CBSE Board 2022 Exams
Ex 6.1,9 Deleted for CBSE Board 2022 Exams
Ex 6.1,11 Important Deleted for CBSE Board 2022 Exams
Misc 3 Important
Ex 6.1,10 Important Deleted for CBSE Board 2022 Exams
Example 44 Important Deleted for CBSE Board 2022 Exams
Finding rate of change
Last updated at Aug. 9, 2021 by Teachoo
Misc. 19 A cylindrical tank of radius 10 m is being filled with wheat at the rate of 314 cubic meter per hour. Then the depth of the wheat is increasing at the rate of (A) 1 m /h (B) 0.1 m/h (C) 1.1 m/h (D) 0.5 m/hLet r be the radius of cylindrical tank & V be the volume of cylindrical tank & h be the depth of the cylindrical tank Given that cylindrical tank of radius 10 m being filled with wheat at the rate of 314 cubic meter per hour i.e. Change if volume of tank is 314 m3/hr. when r = 10 i.e. π π½/π π = 314 m3/hr. when r = 10 We need to find at what rate depth is increasing i.e. we need to find π π/π π Now, ππ/ππ‘ = 314 (π (ππ^2 β))/ππ‘ = 314 (π(π(102)β))/ππ‘ = 314 (π(100πβ))/ππ‘ = 314 100π π π/π π = 314 πβ/ππ‘ = 314/100π πβ/ππ‘ = 314/(100 Γ 3.14) πβ/ππ‘ = 314/314 πβ/ππ‘ = 1 Since depth is in meter & time is in hr So, π π/π π = 1 m/hr. So, A is the correct answer.