

Finding rate of change
Ex 6.1, 1 Deleted for CBSE Board 2022 Exams
Ex 6.1,17 (MCQ) Deleted for CBSE Board 2022 Exams
Example 5 Deleted for CBSE Board 2022 Exams
Ex 6.1,15 Important Deleted for CBSE Board 2022 Exams
Example 6 Deleted for CBSE Board 2022 Exams
Ex 6.1,16 Deleted for CBSE Board 2022 Exams
Ex 6.1, 18 (MCQ) Important Deleted for CBSE Board 2022 Exams
Example 2 Deleted for CBSE Board 2022 Exams
Ex 6.1,2 Deleted for CBSE Board 2022 Exams
Example 49 Deleted for CBSE Board 2022 Exams
Example 3 Deleted for CBSE Board 2022 Exams
Ex 6.1,5 Important Deleted for CBSE Board 2022 Exams
Ex 6.1,3 Deleted for CBSE Board 2022 Exams
Ex 6.1,6 Deleted for CBSE Board 2022 Exams
Ex 6.1,12 Deleted for CBSE Board 2022 Exams
Ex 6.1,13 Important Deleted for CBSE Board 2022 Exams
Misc. 19 (MCQ) Deleted for CBSE Board 2022 Exams
Ex 6.1,14 Deleted for CBSE Board 2022 Exams
Example 43 Important Deleted for CBSE Board 2022 Exams
Ex 6.1,4 Important Deleted for CBSE Board 2022 Exams
Example 42 Important Deleted for CBSE Board 2022 Exams You are here
Example 4 Important Deleted for CBSE Board 2022 Exams
Ex 6.1,7 Deleted for CBSE Board 2022 Exams
Ex 6.1,8 Deleted for CBSE Board 2022 Exams
Ex 6.1,9 Deleted for CBSE Board 2022 Exams
Ex 6.1,11 Important Deleted for CBSE Board 2022 Exams
Misc 3 Important
Ex 6.1,10 Important Deleted for CBSE Board 2022 Exams
Example 44 Important Deleted for CBSE Board 2022 Exams
Finding rate of change
Last updated at April 19, 2021 by Teachoo
Example 42 A car starts from a point P at time t = 0 seconds and stops at point Q. The distance x, in metres, covered by it, in t seconds is given by π₯=π‘^2 (2βπ‘/3). Find the time taken by it to reach Q and also find distance b/w P & Q Given Distance π₯ = t2 (2βπ‘/3) At points P and Q, the Velocity of the car is 0 Let π£ be the velocity of the car π£ = Change in Distance w.r.t ttime π = π π/π π Finding π π£ = π(π‘^2 (2 β π‘/3))/ππ‘ π£ = π(2π‘^2β π‘^3/3)/ππ‘ π£ = 4t β t2 Putting π = 0 4t β t2 = 0 t(4βπ‘)=0 So, t = 0 & t = 4 Thus, it takes 4 seconds to reach from point P to Q Also, Distance PQ = Distance travelled in 4 seconds Finding x at t = 4 π₯ = t2 (2βπ‘/3) π₯ = (4)^2 (2β4/3) = 16 ((6 β 4)/3) = 16 (2/3) = 32/3 π. Hence, Distance PQ = ππ/π π.